Accounting does not require advanced algebra or trigonometry, you may do fine with basic knowledge in Maths. What is hard about accounting is that it involves analyzing, reporting which requires constant attention. Instead of maths, maybe you should think if you are into economics and finance...
Is accounting hard? I am not too good in math.I had B in algebra and C in trig%26amp; trig?
i did business and finance for three years algebra is only used in business statistics if this is what you are intersted in. it involves plotting a busineess' future as in future earnings whether they would make a profit or a loss.
the finance side would be accounting and it does get complicated doing petty cash is simple but it gets harder when doing profit and loss accounts on triple ledger. but i suppose it would be easier nowadays with all the finance programs you can get such as sage. you also need to know how to use spreadsheets as well
Reply:I don't think it is hard. I took a Business course and to my surprise "basic accounting principles" were one of the classes. I was kind of nervous about it. To make a long story short it was my favorite class. It was fun to learn, got a 4.0. Im sure you would be fine.
sweet pea
Tuesday, July 14, 2009
What value of c would give a system with no solution? Math help!!?
x + 2y = 6
cx - 4y =8
Please show all the stepas, to this equation. thanks
What value of c would give a system with no solution? Math help!!?
multiply 1st equation by -2 to match up y coefficients:
-2x - 4y = -12
cx - 4y = 8
if c = -2 there will be no solution, since
-2x - 4y cannot equal both -12 and 8
cx - 4y =8
Please show all the stepas, to this equation. thanks
What value of c would give a system with no solution? Math help!!?
multiply 1st equation by -2 to match up y coefficients:
-2x - 4y = -12
cx - 4y = 8
if c = -2 there will be no solution, since
-2x - 4y cannot equal both -12 and 8
How come some students in my class are in algebra 2 and goes to the high school for math? is there any way i c
please help me
How come some students in my class are in algebra 2 and goes to the high school for math? is there any way i c
They probably tested for higher placement in math. Ask your teacher this question, and express your interest in doing the same thing.
Reply:I almost did that but then I didn't cuz I enrolled into the Challenge program,
So here's what you do: Go to your school counsler and take The Test to see if you qualify or not
How come some students in my class are in algebra 2 and goes to the high school for math? is there any way i c
They probably tested for higher placement in math. Ask your teacher this question, and express your interest in doing the same thing.
Reply:I almost did that but then I didn't cuz I enrolled into the Challenge program,
So here's what you do: Go to your school counsler and take The Test to see if you qualify or not
Can you help me out with this math problem? Show that [x^a(b-c)]/[x^b(a-c)] divided by [(x^b/x^a)^c]=1?
please do not solve this using logarithm method; my teacher told me specifically only to solve this arithmetically
Can you help me out with this math problem? Show that [x^a(b-c)]/[x^b(a-c)] divided by [(x^b/x^a)^c]=1?
x^a(b-c) = x^(ab - ac) = x^(ab)/x^(ac)
x^b(a-c) = x^(ab - bc) = x^(ab)/x^(bc)
Now, [x^a(b-c)]/[x^b(a-c)] =
= [x^(ab)/x^(ac)] / [x^(ab)/x^(bc)] =
= [1/x^(ac)]/[1/x^(bc)] =
= 1/x^(ac) * x^(bc) =
= x^(bc)/x^(ac) =
= [(x^b)^c]/[(x^a)^c] =
= [(x^b/x^a)^c]
QED
Reply:x^[a(b-c)]/[x^b(a-c)]=x^[ab-ac-ab+bc]=x^...
=[x^b/x^a)^c].
this easily leads to the final result desired.
Reply:[x^a(b-c)]/[x^b(a-c)] divided by [(x^b/x^a)^c]
[x^ab-ac /x^ab-bc ] divided by [(x^b-a)^c]
x^ab-ac -ab +bc divided by x^c(b-a)
x^c(b-a) divided by x^c(b-a)
=1
Reply:Let's start with the first half of the problem:
[x^a(b-c)]/[x^b(a-c)]
You can bring the denominator to the top by making the exponent negative:
[x^a(b-c)] * {x^-[b(a-c)]}
When you do all the distributions, you get:
(x^ab-ac) * (x^-ba+bc) or
(x^ab-ac) * (x^-ab+bc)
When you multiply two (same) bases that have exponents, you simply add the exponents, keeping the base:
x^bc-ac
(The ab terms got canceled)
Now we can apply the same rules to the second part of the problem:
[(x^b/x^a)^c]
Remember that this whole term was in the denominator, so we can bring c to the top by reversing its sign:
[(x^b/x^a)^-c]
And we can do the same for a:
[(x^b * x^-a)^-c]=
Now when you have a power raised to another power, you simply multiply the exponents:
(x^-bc * x^ac)
Adding these exponents, we get:
(x^-bc+ac)
Now our full problem looks like:
x^(bc-ac) * x^(-bc+ac) = 1
Now when you add those exponents, you get zero:
x^0 = 1
And anything raised to the zero power is 1:
1 = 1
Can you help me out with this math problem? Show that [x^a(b-c)]/[x^b(a-c)] divided by [(x^b/x^a)^c]=1?
x^a(b-c) = x^(ab - ac) = x^(ab)/x^(ac)
x^b(a-c) = x^(ab - bc) = x^(ab)/x^(bc)
Now, [x^a(b-c)]/[x^b(a-c)] =
= [x^(ab)/x^(ac)] / [x^(ab)/x^(bc)] =
= [1/x^(ac)]/[1/x^(bc)] =
= 1/x^(ac) * x^(bc) =
= x^(bc)/x^(ac) =
= [(x^b)^c]/[(x^a)^c] =
= [(x^b/x^a)^c]
QED
Reply:x^[a(b-c)]/[x^b(a-c)]=x^[ab-ac-ab+bc]=x^...
=[x^b/x^a)^c].
this easily leads to the final result desired.
Reply:[x^a(b-c)]/[x^b(a-c)] divided by [(x^b/x^a)^c]
[x^ab-ac /x^ab-bc ] divided by [(x^b-a)^c]
x^ab-ac -ab +bc divided by x^c(b-a)
x^c(b-a) divided by x^c(b-a)
=1
Reply:Let's start with the first half of the problem:
[x^a(b-c)]/[x^b(a-c)]
You can bring the denominator to the top by making the exponent negative:
[x^a(b-c)] * {x^-[b(a-c)]}
When you do all the distributions, you get:
(x^ab-ac) * (x^-ba+bc) or
(x^ab-ac) * (x^-ab+bc)
When you multiply two (same) bases that have exponents, you simply add the exponents, keeping the base:
x^bc-ac
(The ab terms got canceled)
Now we can apply the same rules to the second part of the problem:
[(x^b/x^a)^c]
Remember that this whole term was in the denominator, so we can bring c to the top by reversing its sign:
[(x^b/x^a)^-c]
And we can do the same for a:
[(x^b * x^-a)^-c]=
Now when you have a power raised to another power, you simply multiply the exponents:
(x^-bc * x^ac)
Adding these exponents, we get:
(x^-bc+ac)
Now our full problem looks like:
x^(bc-ac) * x^(-bc+ac) = 1
Now when you add those exponents, you get zero:
x^0 = 1
And anything raised to the zero power is 1:
1 = 1
How do you call those math/logic problems where A =B, B = C and C = A?
Do you have any examples?
How do you call those math/logic problems where A =B, B = C and C = A?
It's called transitivity
example:
{x =y and y =z } ----%26gt; x =z
Reply:this is call ed the transitive law
Reply:Just like substitution if y= 3x+5 and y=4x+6
since we know y = 3x+5 we can substitute that into the other equation for y:
3x+5 = 4x+6
Now apply this same logic to your example
but instead:
y will be B
3x+5 will be A
4x+6 will be C
so instead of:
y= 3x+5 we have B=A
instead of:
y=4x+6 we have B=C
since B=A and B also =C
we can say that A and C (A=C) must be the same as well.
Hope that was helpful! :)
rose
How do you call those math/logic problems where A =B, B = C and C = A?
It's called transitivity
example:
{x =y and y =z } ----%26gt; x =z
Reply:this is call ed the transitive law
Reply:Just like substitution if y= 3x+5 and y=4x+6
since we know y = 3x+5 we can substitute that into the other equation for y:
3x+5 = 4x+6
Now apply this same logic to your example
but instead:
y will be B
3x+5 will be A
4x+6 will be C
so instead of:
y= 3x+5 we have B=A
instead of:
y=4x+6 we have B=C
since B=A and B also =C
we can say that A and C (A=C) must be the same as well.
Hope that was helpful! :)
rose
What kind of math is this A SQUARE + B SQUARE = C SQUARE?
It's loud math.
But A^2 + B^2 = C^2 is the pythagorean theorem.
What kind of math is this A SQUARE + B SQUARE = C SQUARE?
It's the Pythagorean theorem, used to determine the length of a hypotenuse of a right triangle. It's part of Euclidean geometry.
Reply:It;'s algebra, but there is no way to solve it without either values for two of the variables.
Reply:that is the pythagorean theorem.
it is used in finding the measure of the sides of a right triangle.
for example:
3, 4 and 5
3^2 + 4^2 = 5^2
9 + 16 = 25
25 = 25
Reply:That could be geometry or trigonometry. Or even part of a calculus problem.
Reply:Well, it's the Pythagorean theorem, a fact about geometry.
In the days of Pythagoras, geometry was used to prove results in all kinds of mathematics, or at least as much mathematics was then known; "geometry" MEANT "mathematics". But now that's not the case.
On the other hand, that formula is central to the mathematical definition of "distance", and hence lies at the heart of various areas of mathematics, from statistics to "linear algebra" to "differential geometry". It's also pretty central to trigonometry.
Reply:That is the pythagoras' theorem. We use it to find the length of a side of a right angled triangle.(i.e 1 angle is 90 degree)
The longest side is called the hypotenuse. In this case it is C.
We can use this to find a side of two sides of a right angled triangle is given.
But A^2 + B^2 = C^2 is the pythagorean theorem.
What kind of math is this A SQUARE + B SQUARE = C SQUARE?
It's the Pythagorean theorem, used to determine the length of a hypotenuse of a right triangle. It's part of Euclidean geometry.
Reply:It;'s algebra, but there is no way to solve it without either values for two of the variables.
Reply:that is the pythagorean theorem.
it is used in finding the measure of the sides of a right triangle.
for example:
3, 4 and 5
3^2 + 4^2 = 5^2
9 + 16 = 25
25 = 25
Reply:That could be geometry or trigonometry. Or even part of a calculus problem.
Reply:Well, it's the Pythagorean theorem, a fact about geometry.
In the days of Pythagoras, geometry was used to prove results in all kinds of mathematics, or at least as much mathematics was then known; "geometry" MEANT "mathematics". But now that's not the case.
On the other hand, that formula is central to the mathematical definition of "distance", and hence lies at the heart of various areas of mathematics, from statistics to "linear algebra" to "differential geometry". It's also pretty central to trigonometry.
Reply:That is the pythagoras' theorem. We use it to find the length of a side of a right angled triangle.(i.e 1 angle is 90 degree)
The longest side is called the hypotenuse. In this case it is C.
We can use this to find a side of two sides of a right angled triangle is given.
What is this math equation called: a(squared)+b(squared)=c(square...
it's the Pythagorean Theorem
In any right triangle, the area of the square whose side is the hypotenuse (the side of a right triangle opposite the right angle) is equal to the sum of the areas of the squares on the other two sides.
What is this math equation called: a(squared)+b(squared)=c(square...
The Pythagorean Theorem for right angle triangles.
Reply:its the pythagorean theorem
Reply:The square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.
Pythagorean theorem, after Pythagoras, an ancient Greek geometer.
If one leg making the right angle is 5, and the other leg making the right angle is 4, then the remaining side of the triangle, the hypotenuse, is [5x5]+[4x4]=41.
Reply:Quadratic...? I think...
Reply:pythagorean theorem
Reply:pythagorean theorem
Reply:It is the Pythagorean Theorem.
A(square)+B(square)=C(square)
Remember, it is for right triangles.
Reply:Pythagorean Theorem or if you like to get technical the right triangle theorem.
Reply:i think you're talking about the pythagorean theorem
Reply:pythagoreen theorom
Reply:From Wikipedia, the free encyclopedia
The Pythagorean theorem: The sum of the areas of the two squares on the legs (blue and red) equals the area of the square on the hypotenuse (purple).In mathematics, the Pythagorean theorem or Pythagoras's theorem is a relation in Euclidean geometry between the three sides of a right triangle. In the West, the theorem is named after the Greek mathematician Pythagoras, who is credited with the first abstract proof.
The theorem is as follows:
In any right triangle, the area of the square whose side is the hypotenuse (the side of a right triangle opposite the right angle) is equal to the sum of the areas of the squares on the other two sides.
If we let c be the length of the hypotenuse and a and b be the lengths of the other two sides, the theorem can be expressed as the following equation:
This equation provides a simple relation between the three sides of a right triangle so that if the lengths of any two sides are known, the length of the third side can be found. A generalization of this theorem is the law of cosines, which allows the computation of the length of the third side of any triangle, given the lengths of two sides and the size of the angle between them.
This theorem may have a greater variety of known proofs than any other. The Pythagorean Proposition, a book published in 1940, contains 370 different proofs of Pythagoras's theorem, including one by an American President James Garfield.
The converse of the theorem is also true:
For any three positive numbers a, b, and c such that a2 + b2 = c2, there exists a triangle with sides a, b and c, and every such triangle has a right angle between the sides of lengths a and b.
Reply:pythagorean theorem
Reply:Pythagorean Theorem
Reply:Pythagorean theorem
In any right triangle, the area of the square whose side is the hypotenuse (the side of a right triangle opposite the right angle) is equal to the sum of the areas of the squares on the other two sides.
What is this math equation called: a(squared)+b(squared)=c(square...
The Pythagorean Theorem for right angle triangles.
Reply:its the pythagorean theorem
Reply:The square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.
Pythagorean theorem, after Pythagoras, an ancient Greek geometer.
If one leg making the right angle is 5, and the other leg making the right angle is 4, then the remaining side of the triangle, the hypotenuse, is [5x5]+[4x4]=41.
Reply:Quadratic...? I think...
Reply:pythagorean theorem
Reply:pythagorean theorem
Reply:It is the Pythagorean Theorem.
A(square)+B(square)=C(square)
Remember, it is for right triangles.
Reply:Pythagorean Theorem or if you like to get technical the right triangle theorem.
Reply:i think you're talking about the pythagorean theorem
Reply:pythagoreen theorom
Reply:From Wikipedia, the free encyclopedia
The Pythagorean theorem: The sum of the areas of the two squares on the legs (blue and red) equals the area of the square on the hypotenuse (purple).In mathematics, the Pythagorean theorem or Pythagoras's theorem is a relation in Euclidean geometry between the three sides of a right triangle. In the West, the theorem is named after the Greek mathematician Pythagoras, who is credited with the first abstract proof.
The theorem is as follows:
In any right triangle, the area of the square whose side is the hypotenuse (the side of a right triangle opposite the right angle) is equal to the sum of the areas of the squares on the other two sides.
If we let c be the length of the hypotenuse and a and b be the lengths of the other two sides, the theorem can be expressed as the following equation:
This equation provides a simple relation between the three sides of a right triangle so that if the lengths of any two sides are known, the length of the third side can be found. A generalization of this theorem is the law of cosines, which allows the computation of the length of the third side of any triangle, given the lengths of two sides and the size of the angle between them.
This theorem may have a greater variety of known proofs than any other. The Pythagorean Proposition, a book published in 1940, contains 370 different proofs of Pythagoras's theorem, including one by an American President James Garfield.
The converse of the theorem is also true:
For any three positive numbers a, b, and c such that a2 + b2 = c2, there exists a triangle with sides a, b and c, and every such triangle has a right angle between the sides of lengths a and b.
Reply:pythagorean theorem
Reply:Pythagorean Theorem
Reply:Pythagorean theorem
Help doing math problem! if cosθ = 3/5 and sin θ<0, find: a. sinθ b.secθ c.cscθ d.tan θ e.cotθ?
if cosθ = 3/5 and sin θ%26lt;0, find: a. sinθ b.secθ c.cscθ d.tan θ e.cotθ
How do I do it??
Help doing math problem! if cosθ = 3/5 and sin θ%26lt;0, find: a. sinθ b.secθ c.cscθ d.tan θ e.cotθ?
cosθ = 3/5 --%26gt; secθ = 5/3 [secx=1/cosx]
sinθ = -4/5 --%26gt; csc θ= -5/4 [sin²x= 1- cos²x]
tanθ= -4/3 --%26gt; cot θ= -3/4 [tanx=sinx/cosx]
Saludos.
Reply:Use the Pythagorean trigonometric identity: sin^2 (theta) and cos^2 (theta) = 1.
(3/5)^2 + sin^2 (theta) = 1 = 9/25 + sin^2 (theta) = 1. sin^2 (theta) = 16/25. sin (theta) = 4/5.
sec (theta) = 5/3. csc (theta) = 5/4. tan (theta) = 4/3. cot (theta) = 3/4.
Reply:cos(x) = 3/5
squaring
cos^2(x) = 9/25
1 - sin^2(x) = 9/25 (since cos^2(x) = 1 - sin^2(x))
sin^2(x) = 1 - (9/25) = (25-9)/25
sin^2(x) = 16/25
a) sin(x) = -4/5 (since sinx %26lt;0)
b) secx = 1/cosx = 5/3
c) csc(x) = 1/sinx = -5/4
d) tan(x) = sinx/cosx = -(4/5)/(3/5) = -4/3
e) cotx = 1/tanx = -3/4
Reply:cos(x)=3/5 ----%26gt; sec(x)= 5/3
sin(x) = -4/5 ----%26gt; csc(x)= -5/4
tan(x) = -4/3 -----%26gt; cot(x) =-3/4
Reply:cos = adjacent side/ hypotenuse, so the hypotenuse is 5.
sin is opposite side / hpotenuse
By Pythogoren, theorem= 5^2=3^2+4^2
so sin =4/5, but it is negative. so sin(theta)=-4/5
b)sec(theta)=1/cos(theta)=5/3
c)csc(theta)=1/sin(theta)=-5/4
d)tan(theta)=sin/cos= (-4/5)(3/5)=-4/3
e)cot=1/tan=-3/4
Reply:The answers by lou h is right. This is how to get it
sin= y/r cos= x/r tan= y/x
csc= reciprocal of sin sec= reciprocal of cos cot= reciprocal of tan
since you have cos then you know that x=3 and r=5
just use pythagorean theorem to find y.
x squared plus y squared = r squared
when you do this you find that y=4
since cos%26amp;sec are positive, the 4 other functions all have to be the same. Since sin θ%26lt;0 that means it is neg, which means that all of the others are negative as well.
How do I do it??
Help doing math problem! if cosθ = 3/5 and sin θ%26lt;0, find: a. sinθ b.secθ c.cscθ d.tan θ e.cotθ?
cosθ = 3/5 --%26gt; secθ = 5/3 [secx=1/cosx]
sinθ = -4/5 --%26gt; csc θ= -5/4 [sin²x= 1- cos²x]
tanθ= -4/3 --%26gt; cot θ= -3/4 [tanx=sinx/cosx]
Saludos.
Reply:Use the Pythagorean trigonometric identity: sin^2 (theta) and cos^2 (theta) = 1.
(3/5)^2 + sin^2 (theta) = 1 = 9/25 + sin^2 (theta) = 1. sin^2 (theta) = 16/25. sin (theta) = 4/5.
sec (theta) = 5/3. csc (theta) = 5/4. tan (theta) = 4/3. cot (theta) = 3/4.
Reply:cos(x) = 3/5
squaring
cos^2(x) = 9/25
1 - sin^2(x) = 9/25 (since cos^2(x) = 1 - sin^2(x))
sin^2(x) = 1 - (9/25) = (25-9)/25
sin^2(x) = 16/25
a) sin(x) = -4/5 (since sinx %26lt;0)
b) secx = 1/cosx = 5/3
c) csc(x) = 1/sinx = -5/4
d) tan(x) = sinx/cosx = -(4/5)/(3/5) = -4/3
e) cotx = 1/tanx = -3/4
Reply:cos(x)=3/5 ----%26gt; sec(x)= 5/3
sin(x) = -4/5 ----%26gt; csc(x)= -5/4
tan(x) = -4/3 -----%26gt; cot(x) =-3/4
Reply:cos = adjacent side/ hypotenuse, so the hypotenuse is 5.
sin is opposite side / hpotenuse
By Pythogoren, theorem= 5^2=3^2+4^2
so sin =4/5, but it is negative. so sin(theta)=-4/5
b)sec(theta)=1/cos(theta)=5/3
c)csc(theta)=1/sin(theta)=-5/4
d)tan(theta)=sin/cos= (-4/5)(3/5)=-4/3
e)cot=1/tan=-3/4
Reply:The answers by lou h is right. This is how to get it
sin= y/r cos= x/r tan= y/x
csc= reciprocal of sin sec= reciprocal of cos cot= reciprocal of tan
since you have cos then you know that x=3 and r=5
just use pythagorean theorem to find y.
x squared plus y squared = r squared
when you do this you find that y=4
since cos%26amp;sec are positive, the 4 other functions all have to be the same. Since sin θ%26lt;0 that means it is neg, which means that all of the others are negative as well.
What is that math property that goes "if a+b=c and a+d=c, then b=d"?
Associative Property of Addition
What is that math property that goes "if a+b=c and a+d=c, then b=d"?
Associative Property of Addition
Reply:addiditive property of transition
Reply:associative property of addition
Reply:the property says :
if you add 2 numbers to the same number and each time you get same result then these two numbers are equal
flowering plum
What is that math property that goes "if a+b=c and a+d=c, then b=d"?
Associative Property of Addition
Reply:addiditive property of transition
Reply:associative property of addition
Reply:the property says :
if you add 2 numbers to the same number and each time you get same result then these two numbers are equal
flowering plum
Explain why it doent matter which side of a math equation you bring all the values to when determining a,b,c?
such as, Ax(squared)+Bx+C=0 or x=B+/-[B(squared)-4AC]/2A
[ ]=under radical
Explain why it doent matter which side of a math equation you bring all the values to when determining a,b,c?
by the symmetric property of equality we are able to "flip" an equation...for example
0=2x+4 is the same as 2x+4=0
a quadratic equation will work the same way
[ ]=under radical
Explain why it doent matter which side of a math equation you bring all the values to when determining a,b,c?
by the symmetric property of equality we are able to "flip" an equation...for example
0=2x+4 is the same as 2x+4=0
a quadratic equation will work the same way
Math: Triangle abc is a right triangle (c being 90 deg). the altitude intersects the hypotenuse at D.?
Name ALL geometric means present and plz explain
Math: Triangle abc is a right triangle (c being 90 deg). the altitude intersects the hypotenuse at D.?
Triangles ABC, ACD, and CBD are all similar triangles, meaning their corresponding angles are congruent. (This is probably a theorem in your geometry book, but it's fairly easy to prove. To show that triangles ABC and ACD are similar, just observe that each one contains a right angle and each one contains angle A. Since the measures of the angles in a triangle always add up to the same thing, namely 180 degrees, that means the remaining angles in those triangles must also have the same measures. The proof that ABC and CBD are similar triangles is, well, similar.)
Because triangle ACD is similar to triangle CBD, we have AD/CD = CD/DB (where AD means the measure of line segment AD, etc.). Cross-multiplying, we have (CD)^2 = (AD)(DB); in other words, CD is the geometric mean of AD and DB.
I don't think there are other geometric means in there, at least not without adding more points and line segments, but maybe there's something I'm not seeing.
Math: Triangle abc is a right triangle (c being 90 deg). the altitude intersects the hypotenuse at D.?
Triangles ABC, ACD, and CBD are all similar triangles, meaning their corresponding angles are congruent. (This is probably a theorem in your geometry book, but it's fairly easy to prove. To show that triangles ABC and ACD are similar, just observe that each one contains a right angle and each one contains angle A. Since the measures of the angles in a triangle always add up to the same thing, namely 180 degrees, that means the remaining angles in those triangles must also have the same measures. The proof that ABC and CBD are similar triangles is, well, similar.)
Because triangle ACD is similar to triangle CBD, we have AD/CD = CD/DB (where AD means the measure of line segment AD, etc.). Cross-multiplying, we have (CD)^2 = (AD)(DB); in other words, CD is the geometric mean of AD and DB.
I don't think there are other geometric means in there, at least not without adding more points and line segments, but maybe there's something I'm not seeing.
Math Trivia (3x^-1 y^b z^c) (-y^f z^g?
the "^" symbol means the next 1 digit is an exponent. Only the next 1!
First person to answer correctly gets best answer
Math Trivia (3x^-1 y^b z^c) (-y^f z^g?
(3x^-1 y^b z^c) (-y^f z^g)
-3/x (y^b+f z^c+g)
note; x^-1 is changed to a positive exponent 1/x
also when the bases multiply the exponents will be added.
Reply:-3*y^(b+f)*z^(c+g) / x
First person to answer correctly gets best answer
Math Trivia (3x^-1 y^b z^c) (-y^f z^g?
(3x^-1 y^b z^c) (-y^f z^g)
-3/x (y^b+f z^c+g)
note; x^-1 is changed to a positive exponent 1/x
also when the bases multiply the exponents will be added.
Reply:-3*y^(b+f)*z^(c+g) / x
Challenging math problem. 60ml of solution A is mixed with 120ml of solution B to produce solution C with....?
60ml of solution A is mixed with 120ml of solution B to produce solution C with 8% pure acid. If 80ml of solution A is mixed with 40ml of solution B. 10% acid is produced. how much % acid is in Solution A.
a little guide will help. EXAM TOMOROW
Challenging math problem. 60ml of solution A is mixed with 120ml of solution B to produce solution C with....?
let there be x% acidic of sol. A and y% acidic of sol. B.
60x + 120y = (60+120)*8 = 180*8
x + 2y = 3*8 = 24
80x + 40y = (80+40)*10 = 120*10
2x + y = 3*10 = 30
4x - x = 60 - 24
3x = 36
x = 12%
Reply:first mixed=180ml
8%of it is 14.4ml of pure acid
2nd mixed=120ml
10% is 12ml of pure acid
let x be the concentration of A
let y be the concentration of B
60x+120y=14.4
80x+40y=12
solve for x and y
240x-60x=36-14.4
180x=21.6
x=12%
therefore the solution A is 12%
nil
a little guide will help. EXAM TOMOROW
Challenging math problem. 60ml of solution A is mixed with 120ml of solution B to produce solution C with....?
let there be x% acidic of sol. A and y% acidic of sol. B.
60x + 120y = (60+120)*8 = 180*8
x + 2y = 3*8 = 24
80x + 40y = (80+40)*10 = 120*10
2x + y = 3*10 = 30
4x - x = 60 - 24
3x = 36
x = 12%
Reply:first mixed=180ml
8%of it is 14.4ml of pure acid
2nd mixed=120ml
10% is 12ml of pure acid
let x be the concentration of A
let y be the concentration of B
60x+120y=14.4
80x+40y=12
solve for x and y
240x-60x=36-14.4
180x=21.6
x=12%
therefore the solution A is 12%
nil
I been taking math in advance at a community college (algebra II) and so far i have a C i think i will pass?
the final with a C and in college they give u two option to put the course credit for the college or tranfer it into your high school so u dont need to take algebra II next year, but since im getting a C should i transfer the credit to my high scohol still? do u think i will do bad for precalculus? or should i leave the credit for colleg eand retake algebra II at the high school in my junior year
I been taking math in advance at a community college (algebra II) and so far i have a C i think i will pass?
I think you should leave that credit for college and take it again your junior year. If you want to take precalculus you are going to need a better grade than a C in algebra II or you are going to fail precalculus.
I been taking math in advance at a community college (algebra II) and so far i have a C i think i will pass?
I think you should leave that credit for college and take it again your junior year. If you want to take precalculus you are going to need a better grade than a C in algebra II or you are going to fail precalculus.
MATH HELPPP!!! find the centroid of the triangle with vertices A (2,5) B (-6,-1) and C (6,3)?
find the centroid of the triangle with vertices A (2,5) B (-6,-1) and C (6,3)
THXX so much!!
MATH HELPPP!!! find the centroid of the triangle with vertices A (2,5) B (-6,-1) and C (6,3)?
Hey,
Just apply the formula...for any triangle...Centroid is Given by
( x1 + x2 + x3)/3 , (y1+y2+y3)/3
So here centroid is: (2/3, 7/3) or (.67,2.33)
THXX so much!!
MATH HELPPP!!! find the centroid of the triangle with vertices A (2,5) B (-6,-1) and C (6,3)?
Hey,
Just apply the formula...for any triangle...Centroid is Given by
( x1 + x2 + x3)/3 , (y1+y2+y3)/3
So here centroid is: (2/3, 7/3) or (.67,2.33)
(Math)In the Equation y=axx+bx+c, How can i combine axx+c with bx and how do i put it on a graph?
Please this is one of the few things i need to know
(Math)In the Equation y=axx+bx+c, How can i combine axx+c with bx and how do i put it on a graph?
To put it on a graph just let x equal a series of numbers say 1,2,3,4,5 and then substitute them into the equation and solve for y. Then plot them on a graph.
Reply:y = ax^2 + bx + c
You can't really combine them into one term, if that's what you're asking. All you have to do is use the fact that it's a parabola, and you can obtain
1) the x-intercept(s), if any
2) the y-intercept
3) the vertex
Those would be some sketching guides right there, as soon as you learn how to get them.
(Math)In the Equation y=axx+bx+c, How can i combine axx+c with bx and how do i put it on a graph?
To put it on a graph just let x equal a series of numbers say 1,2,3,4,5 and then substitute them into the equation and solve for y. Then plot them on a graph.
Reply:y = ax^2 + bx + c
You can't really combine them into one term, if that's what you're asking. All you have to do is use the fact that it's a parabola, and you can obtain
1) the x-intercept(s), if any
2) the y-intercept
3) the vertex
Those would be some sketching guides right there, as soon as you learn how to get them.
Ok math buffs and engineers small question in Qs=mC(delta T) what does the 'C' represent?
this is an equasion for sensible heat, M is mass, delta t is the heat differences..... but C i cant make my head work.. thanks all
Ok math buffs and engineers small question in Qs=mC(delta T) what does the 'C' represent?
The specific heat is a property of the particular material. It is the number that is the answer to the question, "How much energy would it take to raise the temperature of one unit of this material one degree?"
Reply:C represents the specific heat... either in constant volume or constant pressure.
Q = m C Delta T
Q = heat
m = mass
C = specific heat at constant volume or constant pressure
Delta T = change in temperature
Reply:hi.
c is specific heat of the substance to which heat is supplied.
:-)
Reply:specific heat
Reply:As everyone has said, specific heat.
Usually expressed in units of Joules/gram/degree C or British Thermal Unit (BTU)/lb/degree F
In US units (the old british units) the specific heat of water is 1.0 BTU/lb/deg F because the BTU was defined as the heat to raise a pound of water by 1 degree
In SI units, the specific heat of water is about 4.18 J/gram/degree C or 1 calorie/gram/degree
Most substances have a specific heat lower than water.
Just as the "specific gravity" of a substance is its density related to water =1, so specific heat related the heat capacity of substances to water as a standard.
sp
Ok math buffs and engineers small question in Qs=mC(delta T) what does the 'C' represent?
The specific heat is a property of the particular material. It is the number that is the answer to the question, "How much energy would it take to raise the temperature of one unit of this material one degree?"
Reply:C represents the specific heat... either in constant volume or constant pressure.
Q = m C Delta T
Q = heat
m = mass
C = specific heat at constant volume or constant pressure
Delta T = change in temperature
Reply:hi.
c is specific heat of the substance to which heat is supplied.
:-)
Reply:specific heat
Reply:As everyone has said, specific heat.
Usually expressed in units of Joules/gram/degree C or British Thermal Unit (BTU)/lb/degree F
In US units (the old british units) the specific heat of water is 1.0 BTU/lb/deg F because the BTU was defined as the heat to raise a pound of water by 1 degree
In SI units, the specific heat of water is about 4.18 J/gram/degree C or 1 calorie/gram/degree
Most substances have a specific heat lower than water.
Just as the "specific gravity" of a substance is its density related to water =1, so specific heat related the heat capacity of substances to water as a standard.
sp
When writing a proof statement in math, what's the best way to disprove a, b, and c as positive integers?
I understand the idea of how to disprove, but I want to know how one would try to disprove the following statement:
If a, b, and c are positive integers with a|(bc), then a|b or a|c
When writing a proof statement in math, what's the best way to disprove a, b, and c as positive integers?
a|(bc) =%26gt; a|b or a|c is true for some choices of a, b, and c (e.g. trivially if a = 1), so you can't disprove it for general a, b, and c.
But the statement you're asked to disprove is stronger -- it asserts this condition for all positive a, b, and c. Therefore, you want to disprove the "all" part, by showing a choice for a, b, and c such that a|(bc) but a|b and a|c are false.
If you're having trouble, think about the case a = bc, which guarantees a|(bc).
Reply:Find a counterexample. Three specific integers a, b, and c where the statement is false. Namely find three specific numbers a, b, and c where a|(bc) but a does not divide either b or c. So a divides the product without dividing either of the factors.
Should not take you long to come up with some examples,
If a, b, and c are positive integers with a|(bc), then a|b or a|c
When writing a proof statement in math, what's the best way to disprove a, b, and c as positive integers?
a|(bc) =%26gt; a|b or a|c is true for some choices of a, b, and c (e.g. trivially if a = 1), so you can't disprove it for general a, b, and c.
But the statement you're asked to disprove is stronger -- it asserts this condition for all positive a, b, and c. Therefore, you want to disprove the "all" part, by showing a choice for a, b, and c such that a|(bc) but a|b and a|c are false.
If you're having trouble, think about the case a = bc, which guarantees a|(bc).
Reply:Find a counterexample. Three specific integers a, b, and c where the statement is false. Namely find three specific numbers a, b, and c where a|(bc) but a does not divide either b or c. So a divides the product without dividing either of the factors.
Should not take you long to come up with some examples,
How can I convert from mx+B form to Ax+By=C Form and what website is a good reference for math questions?
My math teacher is a complete bi*** and does not answer any questions. I need to this and many other things that she does not bother to explain in order to pass her class. Any ideas? P.S. this is actually a geometry class that I took so I would not have to take Algebra. Little did I know at the time that geometry uses Algebra. Grrrrrrrrr!!!!!!!!
How can I convert from mx+B form to Ax+By=C Form and what website is a good reference for math questions?
Yes, Geometry is based on algebra, but yea.
Ok First for MX+B, you need to get the slope as X/-Y)
take the X value in for A in AX+BY=C. Then plug the Y value in for B. For c, take the (0,B) part and plug it into the AX+BY part, and the result of that will be your C vale.
I would reccommend purplemath.com
Reply:y = 2/3x + 6 : y = mx + b : original
0 = 2/3x - y + 6 : 0 = mx - y + b : move y to other side
-6 = 2/3 x - y : move b to other side to get -b = mx - y -- this also is a fractional form of C = Ax + By
2/3 x - y = -6 : turn it around to look more like Ax + By = C
2x - 3y = -18 : multiply all by 3 to clear fraction -- and you have this in Ax + By = C form
The fast way :
Swap the y and the number both sides, changing the sign on both as you do : y = 2/3 x + 6 becomes -6 = 2/3 x - y
Flip the equation : 2/3 x - y = -6
Clear the fraction : 2x - 3y = -18
Reply:To change y = mx + b into standard form, let's look at an example:
y = 3x + 5, bring the 3x to the left side by subtracting it
-3x + y = 5, can't lead with a negative, so let's multiply by -1
-1(-3x + y = 5)
3x - y = -5
that's it. You're at a good site right now for asking questions. Also, study the examples in your text book and see if you can find a study partner in your class.
How can I convert from mx+B form to Ax+By=C Form and what website is a good reference for math questions?
Yes, Geometry is based on algebra, but yea.
Ok First for MX+B, you need to get the slope as X/-Y)
take the X value in for A in AX+BY=C. Then plug the Y value in for B. For c, take the (0,B) part and plug it into the AX+BY part, and the result of that will be your C vale.
I would reccommend purplemath.com
Reply:y = 2/3x + 6 : y = mx + b : original
0 = 2/3x - y + 6 : 0 = mx - y + b : move y to other side
-6 = 2/3 x - y : move b to other side to get -b = mx - y -- this also is a fractional form of C = Ax + By
2/3 x - y = -6 : turn it around to look more like Ax + By = C
2x - 3y = -18 : multiply all by 3 to clear fraction -- and you have this in Ax + By = C form
The fast way :
Swap the y and the number both sides, changing the sign on both as you do : y = 2/3 x + 6 becomes -6 = 2/3 x - y
Flip the equation : 2/3 x - y = -6
Clear the fraction : 2x - 3y = -18
Reply:To change y = mx + b into standard form, let's look at an example:
y = 3x + 5, bring the 3x to the left side by subtracting it
-3x + y = 5, can't lead with a negative, so let's multiply by -1
-1(-3x + y = 5)
3x - y = -5
that's it. You're at a good site right now for asking questions. Also, study the examples in your text book and see if you can find a study partner in your class.
Math Q, can someone help me? Solve for the named variable- 2x+b=c (solve for x)?
I can't remember how to do this, can someone help me?
Solve for the named variable-
2x+b=c (solve for x)
Math Q, can someone help me? Solve for the named variable- 2x+b=c (solve for x)?
Step 1: Subtract b from both sides
2x=c-b
Step 2: Divide both sides by 2
x=(c-b)/2
That's it!
Reply:do you have the variable numbers for a and b???
Reply:2x+b=c (solve for x)
First move all terms containing "x" to one side of the equals and all other terms to the other side.
2x + b - b = c - b
2x = c - b
Now divide both sides of the equation by 2
2x/2 = (c-b)/2
x = (c-b)/2
Reply:2x+b=c
you must first get x by itself
subtract b from ither side
2x+b=c
-b -b
2x=c-b
then divide both sides by 2, so x will be alone
x=c-b/2
Reply:im not sure..but from what i remember i think x=2
but shudnt u know what b %26amp; c = to??
Reply:2x+b=c
2x =c-b
x =(c-b)/2
Solve for the named variable-
2x+b=c (solve for x)
Math Q, can someone help me? Solve for the named variable- 2x+b=c (solve for x)?
Step 1: Subtract b from both sides
2x=c-b
Step 2: Divide both sides by 2
x=(c-b)/2
That's it!
Reply:do you have the variable numbers for a and b???
Reply:2x+b=c (solve for x)
First move all terms containing "x" to one side of the equals and all other terms to the other side.
2x + b - b = c - b
2x = c - b
Now divide both sides of the equation by 2
2x/2 = (c-b)/2
x = (c-b)/2
Reply:2x+b=c
you must first get x by itself
subtract b from ither side
2x+b=c
-b -b
2x=c-b
then divide both sides by 2, so x will be alone
x=c-b/2
Reply:im not sure..but from what i remember i think x=2
but shudnt u know what b %26amp; c = to??
Reply:2x+b=c
2x =c-b
x =(c-b)/2
If i got a C in one semester of pre-calculus, but all my other math grades are A's, am I ok for UCLA and UCI?
I have a "UC" GPA of 4.3 (10thgrade-11th grade) I got the C in the second semester of my junior year. I know they look for other things like test scores and extracurriculars, but I am just worried about the GPA part. I am planning to take a college calculus course at a community college and sending in the grade to show that the "C" was a fluke.
If i got a C in one semester of pre-calculus, but all my other math grades are A's, am I ok for UCLA and UCI?
One semester of C is unlikely to derail your UC application, but do take Calculus at your community college to prove your math skills. You'll be fine.
Reply:It shouldn't deter you that much. Definitely do well in the college calculus course. And if you can manage to go to an actual university during a summer or extension to take a calculus course, that'd be more impressive and you can transfer that anyways. You can maybe consider explaining that C in a short essay for one of the questions.
Reply:It is always a good idea to take college courses while in high school. You will be just fine....
radiata
If i got a C in one semester of pre-calculus, but all my other math grades are A's, am I ok for UCLA and UCI?
One semester of C is unlikely to derail your UC application, but do take Calculus at your community college to prove your math skills. You'll be fine.
Reply:It shouldn't deter you that much. Definitely do well in the college calculus course. And if you can manage to go to an actual university during a summer or extension to take a calculus course, that'd be more impressive and you can transfer that anyways. You can maybe consider explaining that C in a short essay for one of the questions.
Reply:It is always a good idea to take college courses while in high school. You will be just fine....
radiata
Help plz math---HAT 1 (x,y) : A(0,4) B(0,1) C(6,1) D(4,2) E(4,) F(3,5) G(1,5) H(0,4)
A or B or C or D or E or F or G or H?
Help plz math---HAT 1 (x,y) : A(0,4) B(0,1) C(6,1) D(4,2) E(4,) F(3,5) G(1,5) H(0,4)
on the paper soes this question come wth a diagram? or a graph?
spose it shouldbe a triangle, but without the diagram, and all the co-ordinates, (missing the y co-ordinate in e) is hard to tell.
try asking again and explain what the diagram looks like
Reply:Q unclear. what's HAT? and E is incomplete.
Help plz math---HAT 1 (x,y) : A(0,4) B(0,1) C(6,1) D(4,2) E(4,) F(3,5) G(1,5) H(0,4)
on the paper soes this question come wth a diagram? or a graph?
spose it shouldbe a triangle, but without the diagram, and all the co-ordinates, (missing the y co-ordinate in e) is hard to tell.
try asking again and explain what the diagram looks like
Reply:Q unclear. what's HAT? and E is incomplete.
How do you get the square root of a number in c++ without the sqrt function? (In math terms)?
Thanks.
How do you get the square root of a number in c++ without the sqrt function? (In math terms)?
Start with a guess, say x which will incorrect by dx. Square your guess:
(x + dx) = x^2 + 2dx + dx^2
ignoring the dx^2 because it will become very small, 2dx is approximately the error. Deduct the square of you guess from the result and divide by 2, add this result to your guess and keep going until you hit the correct value.
_
Reply:Use the brute force method try each number in sequence from 1
Reply:you can use a method which is called newtons method or something like that. You say 'n' is the number you want to find the root of and 'x' is a starting guess. The lines are:
int n = 4; /* or any other number */
int x = 1; /* or any number except 0 */
x = ((x+ (n / x) / 2);
I might have used too many parentheses. Anyways, here is how it works, if you don't already understand. 'x' can be any number except 0, but the closer 'g' is to the square root of 'x', the less times you will have to do the formula. You are basically starting with any number, it being a factor of 'n'.
(n / x) finds the other factor. This plus 'x' and then divided by 2 finds the mean of the two factors and stores this as the new 'x'. Every iteration of this formula causes 'x' to get closer and closer to the square root of 'n'. It is suprisingly fast, taking only 5 or 6 cycles for maximum precision if your guess is fairly close. I'm sure you could just put it in a for() loop for a large number of iterations to obtain a very close estimate.
Reply:It very simple to calculate square root of a number with out using sqrt function.
first assume a number as sqrt and apply newton repson method. u will get sqrt of any number.
How do you get the square root of a number in c++ without the sqrt function? (In math terms)?
Start with a guess, say x which will incorrect by dx. Square your guess:
(x + dx) = x^2 + 2dx + dx^2
ignoring the dx^2 because it will become very small, 2dx is approximately the error. Deduct the square of you guess from the result and divide by 2, add this result to your guess and keep going until you hit the correct value.
_
Reply:Use the brute force method try each number in sequence from 1
Reply:you can use a method which is called newtons method or something like that. You say 'n' is the number you want to find the root of and 'x' is a starting guess. The lines are:
int n = 4; /* or any other number */
int x = 1; /* or any number except 0 */
x = ((x+ (n / x) / 2);
I might have used too many parentheses. Anyways, here is how it works, if you don't already understand. 'x' can be any number except 0, but the closer 'g' is to the square root of 'x', the less times you will have to do the formula. You are basically starting with any number, it being a factor of 'n'.
(n / x) finds the other factor. This plus 'x' and then divided by 2 finds the mean of the two factors and stores this as the new 'x'. Every iteration of this formula causes 'x' to get closer and closer to the square root of 'n'. It is suprisingly fast, taking only 5 or 6 cycles for maximum precision if your guess is fairly close. I'm sure you could just put it in a for() loop for a large number of iterations to obtain a very close estimate.
Reply:It very simple to calculate square root of a number with out using sqrt function.
first assume a number as sqrt and apply newton repson method. u will get sqrt of any number.
Math question What is the L.C.M for numbers 72 and 200is it 1,800?
Yes, it the LCM is 1800.
I'm guessing that you would like to know why, and how you can figure out other questions like this.
Here's how I go about it.
We want to factor each number into all the prime numbers that multiply to create the number.
What's a prime number? Just a number that can't be broken down into two other numbers multiplied together.
I like to start with small numbers (2, 3, 5) and work my way up.
So, 72 can be created by 2*36
Which can be 2*2*18
or 2*2*2*9
or 2*2*2*3*3
and if we check to make sure we didn't make a mistake,
2*2*2*3*3=72
2 and 3 can only be created by multiply themselves by the number 1, so we've broken down 72 as far as it will go.
Now, onto 200.
2*100
2*2*50
2*2*2*25
2*2*2*5*5=200
The Least Common Multiple will be created when we multiply numbers that includes each of the prime numbers that make up 72 and 200.
72 has three 2's and two 3's, so we'll need to use at least that many 2's and 3's.
200 has three 2's and two 5's, so we'll need to use at least those.
But, here's the part that makes this the LEAST Common Multiple, we don't have to use ALL the numbers, just enough so that we have as many as either of the two original numbers.
We need at least three 2's. But we don't need any more than that because neither 72 or 200 have more than three 2's.
We need at least two 3's and we need at least two 5's.
When we multiply 2*2*2*3*3*5*5 we get 1,800.
Yea! You found it!
Good luck.
Math question What is the L.C.M for numbers 72 and 200is it 1,800?
You are correct, the L.C.M. is 1,800. Below is the link to an online calculator.
Reply:yes. it's 1800.
Reply:You are absolutely correct!
I'm guessing that you would like to know why, and how you can figure out other questions like this.
Here's how I go about it.
We want to factor each number into all the prime numbers that multiply to create the number.
What's a prime number? Just a number that can't be broken down into two other numbers multiplied together.
I like to start with small numbers (2, 3, 5) and work my way up.
So, 72 can be created by 2*36
Which can be 2*2*18
or 2*2*2*9
or 2*2*2*3*3
and if we check to make sure we didn't make a mistake,
2*2*2*3*3=72
2 and 3 can only be created by multiply themselves by the number 1, so we've broken down 72 as far as it will go.
Now, onto 200.
2*100
2*2*50
2*2*2*25
2*2*2*5*5=200
The Least Common Multiple will be created when we multiply numbers that includes each of the prime numbers that make up 72 and 200.
72 has three 2's and two 3's, so we'll need to use at least that many 2's and 3's.
200 has three 2's and two 5's, so we'll need to use at least those.
But, here's the part that makes this the LEAST Common Multiple, we don't have to use ALL the numbers, just enough so that we have as many as either of the two original numbers.
We need at least three 2's. But we don't need any more than that because neither 72 or 200 have more than three 2's.
We need at least two 3's and we need at least two 5's.
When we multiply 2*2*2*3*3*5*5 we get 1,800.
Yea! You found it!
Good luck.
Math question What is the L.C.M for numbers 72 and 200is it 1,800?
You are correct, the L.C.M. is 1,800. Below is the link to an online calculator.
Reply:yes. it's 1800.
Reply:You are absolutely correct!
Math question What is the L.C.M for numbers 72 and 200?
what is the lowest common multipul for 72 and 200
Math question What is the L.C.M for numbers 72 and 200?
First find the factors of each one.. take ALL of the common factors and then each of the not common factors...
72 = 2*36= 2*2*18=2*2*2*9=2*2*2*3*3
200 = 2*100=2*2*50=2*2*2*25=2*2*2*5*5
common factors = 2*2*2
not common factors = 3*3 and 5*5
take them together.. and get 2*2*2*3*3*5*5=10*10*18= 1800
Reply:1800
medium
Math question What is the L.C.M for numbers 72 and 200?
First find the factors of each one.. take ALL of the common factors and then each of the not common factors...
72 = 2*36= 2*2*18=2*2*2*9=2*2*2*3*3
200 = 2*100=2*2*50=2*2*2*25=2*2*2*5*5
common factors = 2*2*2
not common factors = 3*3 and 5*5
take them together.. and get 2*2*2*3*3*5*5=10*10*18= 1800
Reply:1800
medium
I am taking computer science in the fall , what kind of math would be involved, i will be learning c++?
What jobs could i get when I am finished the course
i will be learning c++ and other computer languages, what skills should I be good at to succeed in this course
I am taking computer science in the fall , what kind of math would be involved, i will be learning c++?
some good prereq's for this class are Algebra I, Geometry, and Algebra II maybe even a little precalc not much though!
i will be learning c++ and other computer languages, what skills should I be good at to succeed in this course
I am taking computer science in the fall , what kind of math would be involved, i will be learning c++?
some good prereq's for this class are Algebra I, Geometry, and Algebra II maybe even a little precalc not much though!
I need to convinve my math teacher to raise my grade from a C to at least a B. what do i say?
without that grade my gpa is a 3.8, so raising this score is very important for me.
this was a calculus 1 class which i had somehow placed into without having taken precalulus or any math for that matter in 3 years. she knows that i had put alot of effort into studying but i dont thing that means much to her.
any suggestion is appreciated.
thank youi
I need to convinve my math teacher to raise my grade from a C to at least a B. what do i say?
Ask your math teacher to give the class a couple of extra tests so you can prove you deserve a 'B'. Your grade needs to be earned.
Reply:Mrs. Calculus teacher...I am REALLY concerned about my low grade in your class and was wondering if there are any extra assignments I could do to earn extra credit in this course to raise my grade from a C to at least a B. I am willing to GO TO ANY LENGTHS to improve this grade. Is it possible for me to do this before the end of the semester? THANK YOU!
Reply:Ask your teacher for extra work or extra credit opportunities.
this was a calculus 1 class which i had somehow placed into without having taken precalulus or any math for that matter in 3 years. she knows that i had put alot of effort into studying but i dont thing that means much to her.
any suggestion is appreciated.
thank youi
I need to convinve my math teacher to raise my grade from a C to at least a B. what do i say?
Ask your math teacher to give the class a couple of extra tests so you can prove you deserve a 'B'. Your grade needs to be earned.
Reply:Mrs. Calculus teacher...I am REALLY concerned about my low grade in your class and was wondering if there are any extra assignments I could do to earn extra credit in this course to raise my grade from a C to at least a B. I am willing to GO TO ANY LENGTHS to improve this grade. Is it possible for me to do this before the end of the semester? THANK YOU!
Reply:Ask your teacher for extra work or extra credit opportunities.
Math question. What will be the TOTAL score when C. Ronaldo scores 2 goals?
a) in every remaining Prem game.
b) in every remaining FA Cup game and Final.
c) in every remaining C.L. game and Final.
Just add 'em up.
Math question. What will be the TOTAL score when C. Ronaldo scores 2 goals?
FA Cup = 10
Champions league = 14
League = 28
so total would be = 52 ?
and 10 points to me yeah ?
Reply:I will murder him dead
Reply:dunno cant be bothered to work it out, he wont tho, he cant handle playing the decent sides, we'll see how he plays when he's up against Gael "the pace" clichy he wont stand a chance!
Reply:it all equals golden boot.
Reply:A lot!
Reply:I am thinking about my tactics to kill him when in the sunshine falls on him.... Just Joking.....
He will be the golden boot winner ok? Peace :)
Reply:Happiness in abundance for United fans and the Treble.
Reply:Can't count I don't have enough fingers to do it.
But I guess he will score a lot of goals.
Reply:28
10
14
and the total = 1 ...golden boot!! x
b) in every remaining FA Cup game and Final.
c) in every remaining C.L. game and Final.
Just add 'em up.
Math question. What will be the TOTAL score when C. Ronaldo scores 2 goals?
FA Cup = 10
Champions league = 14
League = 28
so total would be = 52 ?
and 10 points to me yeah ?
Reply:I will murder him dead
Reply:dunno cant be bothered to work it out, he wont tho, he cant handle playing the decent sides, we'll see how he plays when he's up against Gael "the pace" clichy he wont stand a chance!
Reply:it all equals golden boot.
Reply:A lot!
Reply:I am thinking about my tactics to kill him when in the sunshine falls on him.... Just Joking.....
He will be the golden boot winner ok? Peace :)
Reply:Happiness in abundance for United fans and the Treble.
Reply:Can't count I don't have enough fingers to do it.
But I guess he will score a lot of goals.
Reply:28
10
14
and the total = 1 ...golden boot!! x
What does the asterisk mean in the math formula X = A + (B * C) ?
It means multiply. This asterisk sign is used in almost all computer keyboards to represent "Mutiply". It must be there also from where you have typed your question.
What does the asterisk mean in the math formula X = A + (B * C) ?
When you see an asterisk (*), in means multiplication. It comes from the use of * in several programming languages to represent the operation in code. You may also see x^2 to represent "two squared". Some people would write that as x**2. Same thing, it comes from computer coding and the fact that you don't have superscript keys on your keyboard.
x doesn't get used because it's the name of a variable and it's confusing if you use it both as a name and as the symbol for an operation.
Reply:* - Multiplication
/ - Division
Still can't understand y they dont use 'x' for multiplication
Reply:the asterix just means to multiply...for example
x=a+(B*C)
9=1+(2*4)
Reply:It is multiplication.
Reply:it could be multiplication or it could be a fuction
Reply:X=A+(B 'times' C)
cvs
What does the asterisk mean in the math formula X = A + (B * C) ?
When you see an asterisk (*), in means multiplication. It comes from the use of * in several programming languages to represent the operation in code. You may also see x^2 to represent "two squared". Some people would write that as x**2. Same thing, it comes from computer coding and the fact that you don't have superscript keys on your keyboard.
x doesn't get used because it's the name of a variable and it's confusing if you use it both as a name and as the symbol for an operation.
Reply:* - Multiplication
/ - Division
Still can't understand y they dont use 'x' for multiplication
Reply:the asterix just means to multiply...for example
x=a+(B*C)
9=1+(2*4)
Reply:It is multiplication.
Reply:it could be multiplication or it could be a fuction
Reply:X=A+(B 'times' C)
cvs
C++ program how to check a math problem?
The part of my program I am working on is supposed to give the user random multiplication problems, the user gives an answer, then the program says correct or incorrect. 2 Questions
1. How do I check to get the real answer?
2. If it is incorrect I have to let them retry the same problem up to 3 times. Since I am using a random # generator in a separate function I don't know how to make the exact same problem keep coming up.
This is what I have so far but I get an error
non-lvalue in assignment
what does this mean?
for(i=1;i%26lt;=PROBLEMS;i++)
{
num1=randIntBetween(minNum, maxNum);
num2=randIntBetween(2, maxNum);
cout%26lt;%26lt;i%26lt;%26lt;")"%26lt;%26lt;num1%26lt;%26lt;"x"%26lt;%26lt;num2%26lt;%26lt;"=";
cin%26gt;%26gt;stuAnswer;
num1 * num2 = trueAnswer;
if (stuAnswer == trueAnswer)
{cout%26lt;%26lt;"Correct!";
numRight++;
}
C++ program how to check a math problem?
First, change num1 * num2 = trueAnswer;
to:
trueAnswer = num1 * num2;
1. How do I check to get the real answer?
2. If it is incorrect I have to let them retry the same problem up to 3 times. Since I am using a random # generator in a separate function I don't know how to make the exact same problem keep coming up.
This is what I have so far but I get an error
non-lvalue in assignment
what does this mean?
for(i=1;i%26lt;=PROBLEMS;i++)
{
num1=randIntBetween(minNum, maxNum);
num2=randIntBetween(2, maxNum);
cout%26lt;%26lt;i%26lt;%26lt;")"%26lt;%26lt;num1%26lt;%26lt;"x"%26lt;%26lt;num2%26lt;%26lt;"=";
cin%26gt;%26gt;stuAnswer;
num1 * num2 = trueAnswer;
if (stuAnswer == trueAnswer)
{cout%26lt;%26lt;"Correct!";
numRight++;
}
C++ program how to check a math problem?
First, change num1 * num2 = trueAnswer;
to:
trueAnswer = num1 * num2;
How would you solve the math problem - a(x-3) +c(x-3) ?
[:
How would you solve the math problem - a(x-3) +c(x-3) ?
is it bedmas????? sorry i dont think i can help im just in grade 6........is it the same as bedmas?????????
Reply:its the same as factoring by grouping a quadratic so
(-a+c) ( x-3)
How would you solve the math problem - a(x-3) +c(x-3) ?
is it bedmas????? sorry i dont think i can help im just in grade 6........is it the same as bedmas?????????
Reply:its the same as factoring by grouping a quadratic so
(-a+c) ( x-3)
Math help how do i prove that if a|c and b|c then ab|c?
prove if a|c and b|c then ab|c
how do i go about doing this?? help!
Math help how do i prove that if a|c and b|c then ab|c?
This is not true, as stated.
For example, 4|12, and 6|12, but it is not true that 24|12.
.
how do i go about doing this?? help!
Math help how do i prove that if a|c and b|c then ab|c?
This is not true, as stated.
For example, 4|12, and 6|12, but it is not true that 24|12.
.
I was accepted to a university, but i cant get ENG or MATH 101 so I have to go c. college for them, what to d
My SAT scores arent high enough to meet the requirements, so the univ. said i have to go to c. college for those classes. I also would have to go to university for the rest of my classes. So, my question is, what do i do?...go to university and c. college OR just go to c. college and transfer out next year?..plz help asap!!..thnak you for your replies ppl :D
I was accepted to a university, but i cant get ENG or MATH 101 so I have to go c. college for them, what to d
Are you absolutely certain that the university won't let you test out of these subjcts, like with a CLEP test? Or have you looked into Adult Ed in your area?
I'd get the classes any way I could and go to the University.
Reply:Its the same thing basically. Either way you'll be attending community college. Its just a matter of preference whether you want to do both simultaneously or one at a time. Only you can answer that.
gardenia
I was accepted to a university, but i cant get ENG or MATH 101 so I have to go c. college for them, what to d
Are you absolutely certain that the university won't let you test out of these subjcts, like with a CLEP test? Or have you looked into Adult Ed in your area?
I'd get the classes any way I could and go to the University.
Reply:Its the same thing basically. Either way you'll be attending community college. Its just a matter of preference whether you want to do both simultaneously or one at a time. Only you can answer that.
gardenia
Follow up math/statistics question: what does c mean in 40c15?
trying to translate to excel
Follow up math/statistics question: what does c mean in 40c15?
C means combination.
combination formula:
nCr = n! / [ (n - r)! * r!]
n = number of trials
r = rate
for example:
There are 4 books. How many ways can 2 out of 4 can be chosen?
use the combination formula:
number of trials n = 4
rate r = 2
so 4C2 = 4! / [ (4 - 2)! * 2! ] = 6
Reply:Joezen,
I thought the letter C is average in school subject
also C is celcius
Reply:In general, nCm means possible combinations from a set of n objects, taken m at a time. In particular.
nPm means permutations from a set of n objects taken m at a time.
In combinations, the order of choice does not matter while it does in permutations. (1,2,3) and (2,3,1) are the same combination but they are not the same permutation.
The general solution for nCm is n factorial / (m factorial times (n-m factorial)).
The general solution for nPm is n factorial / (n-m) factorial
Follow up math/statistics question: what does c mean in 40c15?
C means combination.
combination formula:
nCr = n! / [ (n - r)! * r!]
n = number of trials
r = rate
for example:
There are 4 books. How many ways can 2 out of 4 can be chosen?
use the combination formula:
number of trials n = 4
rate r = 2
so 4C2 = 4! / [ (4 - 2)! * 2! ] = 6
Reply:Joezen,
I thought the letter C is average in school subject
also C is celcius
Reply:In general, nCm means possible combinations from a set of n objects, taken m at a time. In particular.
nPm means permutations from a set of n objects taken m at a time.
In combinations, the order of choice does not matter while it does in permutations. (1,2,3) and (2,3,1) are the same combination but they are not the same permutation.
The general solution for nCm is n factorial / (m factorial times (n-m factorial)).
The general solution for nPm is n factorial / (n-m) factorial
Another math probem for u guys, c if u can slove?
hatties age this year is a prime # , in 2 yrs her age will be a perfect sqaure age , at age 55 hattie will retire, wats the oldest hattie can be this yr?
Another math probem for u guys, c if u can slove?
47
The highest (odd perfect square - 2) less than 55.
If the "oldest" restriction were not present, then 23, 7 and 2 would also be possible answers. Once we get past 2, we are only interested in odd perfect squares since the prime #s %26gt; 2 are all odd.
Reply:May be 23years or 47 years
23 and 47 are both prime numbers
after 2 years both will become perfect square - 25 and 49
The oldest person this year is at the age of 47years.
Reply:Hattie is not yet 55 years of age, so let's find the first perfect square less than 55. That number is 49 (7x7). Two less than 49 is 47 which is a prime number - voila! That's the answer! Hattie is now 47 years old.
Reply:47 as nearest perfect square is 49.
Reply:The highest perfect square below 55 is 49, and 2 less than 49 is 47, which is prime... so Hattie is 47.
Reply:Hattie at prime age now and
a perfect square age in 2 years
He's less than 55 years old
so he's 47 years now, in 2 years he'll be 49.
Reply:47 (7 x 7 is 49, minus 2)
Reply:hattie can be either 23 or 47,but as you said oldest,hattie is now 47.
47 is a prime no.
47+2=49(7*7)
Thus,47+2=49, is a perfect square.
thats why hattie is now 47
Reply:hattie will retire at 55 so her age is less than 55
perfect sqaure age less than 55 are 49,36,25 but
49-2=47 is prime
36-2=34 isn't prime
25-2=23 is prime
as hattie is 47 or 23 this year
Reply:well everyone else seems to be on the right track so there is really no need for me to answer the question right!!!
Reply:At 55 Hatties will retire, means he hasn't.
So he must be less than 55.
Looking at all the prime numbers below 55 backwards.
53, 51, 47, 43, 41, 37, ........
I would say 47.
coz 47 is a prime number, and 47+2=49, which is 7*7.
Another math probem for u guys, c if u can slove?
47
The highest (odd perfect square - 2) less than 55.
If the "oldest" restriction were not present, then 23, 7 and 2 would also be possible answers. Once we get past 2, we are only interested in odd perfect squares since the prime #s %26gt; 2 are all odd.
Reply:May be 23years or 47 years
23 and 47 are both prime numbers
after 2 years both will become perfect square - 25 and 49
The oldest person this year is at the age of 47years.
Reply:Hattie is not yet 55 years of age, so let's find the first perfect square less than 55. That number is 49 (7x7). Two less than 49 is 47 which is a prime number - voila! That's the answer! Hattie is now 47 years old.
Reply:47 as nearest perfect square is 49.
Reply:The highest perfect square below 55 is 49, and 2 less than 49 is 47, which is prime... so Hattie is 47.
Reply:Hattie at prime age now and
a perfect square age in 2 years
He's less than 55 years old
so he's 47 years now, in 2 years he'll be 49.
Reply:47 (7 x 7 is 49, minus 2)
Reply:hattie can be either 23 or 47,but as you said oldest,hattie is now 47.
47 is a prime no.
47+2=49(7*7)
Thus,47+2=49, is a perfect square.
thats why hattie is now 47
Reply:hattie will retire at 55 so her age is less than 55
perfect sqaure age less than 55 are 49,36,25 but
49-2=47 is prime
36-2=34 isn't prime
25-2=23 is prime
as hattie is 47 or 23 this year
Reply:well everyone else seems to be on the right track so there is really no need for me to answer the question right!!!
Reply:At 55 Hatties will retire, means he hasn't.
So he must be less than 55.
Looking at all the prime numbers below 55 backwards.
53, 51, 47, 43, 41, 37, ........
I would say 47.
coz 47 is a prime number, and 47+2=49, which is 7*7.
Math question solve for sD=C-s divided by n?
Solve D = (c-s)/n, for s?
Dn - c = -s
c - Dn = s.
Math question solve for sD=C-s divided by n?
are you saying solve for s?
D=(C-s) / n
Dn= C-s
s= C-Dn
Dn - c = -s
c - Dn = s.
Math question solve for sD=C-s divided by n?
are you saying solve for s?
D=(C-s) / n
Dn= C-s
s= C-Dn
Math Q??? I want 2 c if u peoples can figure it out (HEHE)?
So... Ellen drew a square with an area of 25 square inches. What was the length of the sides of her square?
Explain how u got the answer
I got it 4 homework tonight (already figured it out)
Not hard if u passed 4th grade
Math Q??? I want 2 c if u peoples can figure it out (HEHE)?
are you ok? because you should have known this in the third grade. 5 uincase you were wondering p=s². and just so you know s means side, and s² means side times side.
Reply:5 sq. in. Are you in 4th grade? I'm 1 grade higher than you. We call the 3rd graders tird graders and the fourth graders ancle biting 4th graders. I know it's dumb. You have to multiply length times width and since all sides of a square are always the same length, you have to try the first thing that comes to mind, 5x5 wich equals 25 and that equals the area (25 sq. in.). Get it?
Reply:each side is 5 inches, 5 squared is equal to 25
area is calculated: length multiplied by width, and all sides of a square are equal to each other
Reply:The square root of 25 is 5, so the sides of the square are each 5 inches long.
Reply:u have 2 find the square root of 25. it's that simple. the answer would b 5.
what grade r u in? 'cause this was 2 easy.
Reply:each side is 5 inches, what is the square root of 25.....5 (5x5 is 25)
Reply:Yola Chica! It's 5 inches per side cuz 5 times 5 is 25 and i got it too! ^.^
o
Reply:5....just square root!
Reply:5 because that's what everyone else said
Reply:each side is 6.25 inches
oops! I messed up. the person above me got it right! lol
Reply:ok why is this a riddle?
Reply:5.....r u sure dat u got da answer??? maybe u r saying u got da answer so u dun feel stupid...if im rite i deserve 10 points
aster
Explain how u got the answer
I got it 4 homework tonight (already figured it out)
Not hard if u passed 4th grade
Math Q??? I want 2 c if u peoples can figure it out (HEHE)?
are you ok? because you should have known this in the third grade. 5 uincase you were wondering p=s². and just so you know s means side, and s² means side times side.
Reply:5 sq. in. Are you in 4th grade? I'm 1 grade higher than you. We call the 3rd graders tird graders and the fourth graders ancle biting 4th graders. I know it's dumb. You have to multiply length times width and since all sides of a square are always the same length, you have to try the first thing that comes to mind, 5x5 wich equals 25 and that equals the area (25 sq. in.). Get it?
Reply:each side is 5 inches, 5 squared is equal to 25
area is calculated: length multiplied by width, and all sides of a square are equal to each other
Reply:The square root of 25 is 5, so the sides of the square are each 5 inches long.
Reply:u have 2 find the square root of 25. it's that simple. the answer would b 5.
what grade r u in? 'cause this was 2 easy.
Reply:each side is 5 inches, what is the square root of 25.....5 (5x5 is 25)
Reply:Yola Chica! It's 5 inches per side cuz 5 times 5 is 25 and i got it too! ^.^
o
Reply:5....just square root!
Reply:5 because that's what everyone else said
Reply:each side is 6.25 inches
oops! I messed up. the person above me got it right! lol
Reply:ok why is this a riddle?
Reply:5.....r u sure dat u got da answer??? maybe u r saying u got da answer so u dun feel stupid...if im rite i deserve 10 points
aster
I need help with math/ Advanced modeling and functions a/bx+c/d=e x=?
"a" "c" over "bx" plus "d" = "e"? what does "x" equal
Or
a/bx+c/d=e x=?
I need help with math/ Advanced modeling and functions a/bx+c/d=e x=?
x = (e-c/d)*b/a
Or
a/bx+c/d=e x=?
I need help with math/ Advanced modeling and functions a/bx+c/d=e x=?
x = (e-c/d)*b/a
Tricky....Math..For all real numbers b and c such that the product of c and 3 is b, which of the following....
expressions represents the sum of c and 3 in terms of b?
A. B+3
B. 3b+3
C.3(b+3)
D.b+3 over 3
E. b over 3 + 3
Tricky....Math..For all real numbers b and c such that the product of c and 3 is b, which of the following....
c*3 = b
=%26gt; c= b/3
=%26gt; c+3 = b/3 + 3
=%26gt; your answer is e
Reply:The produce of c and 3 is b. Product means multiply, so:
c x 3 = b
divide both sides by 3:
c = b / 3
sum of c and 3 is c + 3
You know that c = b/3, so substitute:
c + 3 = (b/3) + 3
Answer E!
A. B+3
B. 3b+3
C.3(b+3)
D.b+3 over 3
E. b over 3 + 3
Tricky....Math..For all real numbers b and c such that the product of c and 3 is b, which of the following....
c*3 = b
=%26gt; c= b/3
=%26gt; c+3 = b/3 + 3
=%26gt; your answer is e
Reply:The produce of c and 3 is b. Product means multiply, so:
c x 3 = b
divide both sides by 3:
c = b / 3
sum of c and 3 is c + 3
You know that c = b/3, so substitute:
c + 3 = (b/3) + 3
Answer E!
Math question : 1/A + 1/B +1/C = 3/7?
1/A + 1/B +1/C = 3/7
A, B, C are all different numbers.
I know the answers. A=4, B=7,C=28, but I don't know the steps.
Is there a formula or a logical way to solve this problem?
Math question : 1/A + 1/B +1/C = 3/7?
there is a logical way to indicate solutions
find smallest A such that 1/ A %26lt; 3/7
A= 4
Now if A = 4
1/B+1/C = 3/7 -1/4 = 5/28
5/28 = (1+4)/28 = 1/28+1/7
(2+3)/28 no
if we take A = 5 we may get more solutions
1/B+1/C= 3/7-1/5= 8/35
= (1+7)/35 = 1/35+1/5 allow if duplicates permitted else no
no other
take A =6 and we get
1/B+1/C = 3/7-1/6 = 11/42
no other solution as 11/42 is not sum of reciprocal
Reply:Normally you 'clear the denominator' by multipling by the product of the denoms (ABC)
-%26gt; BC+AC+AB=3ABC/7 , but I don't see how that helps here.l
How about reciprocating the whole thing:
1/[1/A+1/B+1/C] = 7/3
[A+B+C]/ABC = 7/3
[A+B+C]/(ABC/3) = 7 , which says that whatever ABC is it must have
Possible choices are
A,B,C, ABC,
1,3,7, 21 , no sol
1,4,7, 28, -%26lt; bingo....
So, the trick is to notice sum must have 7 as a factor, and the product, ABC, must have 3 as a factor.
Reply:the LCD will be 7 or multiple/s of 7
it cannot be 7 since the A,B,C are different
so it can be 6/14 or 9/21 or 12/28
but the denominator has got to be LCD of 4,7 and 28
so it has to be 12/28
so now it has to be 4/28,7/28 and 1/28
so A=4,B=7 and C=28
A, B, C are all different numbers.
I know the answers. A=4, B=7,C=28, but I don't know the steps.
Is there a formula or a logical way to solve this problem?
Math question : 1/A + 1/B +1/C = 3/7?
there is a logical way to indicate solutions
find smallest A such that 1/ A %26lt; 3/7
A= 4
Now if A = 4
1/B+1/C = 3/7 -1/4 = 5/28
5/28 = (1+4)/28 = 1/28+1/7
(2+3)/28 no
if we take A = 5 we may get more solutions
1/B+1/C= 3/7-1/5= 8/35
= (1+7)/35 = 1/35+1/5 allow if duplicates permitted else no
no other
take A =6 and we get
1/B+1/C = 3/7-1/6 = 11/42
no other solution as 11/42 is not sum of reciprocal
Reply:Normally you 'clear the denominator' by multipling by the product of the denoms (ABC)
-%26gt; BC+AC+AB=3ABC/7 , but I don't see how that helps here.l
How about reciprocating the whole thing:
1/[1/A+1/B+1/C] = 7/3
[A+B+C]/ABC = 7/3
[A+B+C]/(ABC/3) = 7 , which says that whatever ABC is it must have
Possible choices are
A,B,C, ABC,
1,3,7, 21 , no sol
1,4,7, 28, -%26lt; bingo....
So, the trick is to notice sum must have 7 as a factor, and the product, ABC, must have 3 as a factor.
Reply:the LCD will be 7 or multiple/s of 7
it cannot be 7 since the A,B,C are different
so it can be 6/14 or 9/21 or 12/28
but the denominator has got to be LCD of 4,7 and 28
so it has to be 12/28
so now it has to be 4/28,7/28 and 1/28
so A=4,B=7 and C=28
Will i make honer roll? i have a A in every class except in math i have a C?
The rules change from school to school, but traditionally, you would not be on the honor roll with one C.
Will i make honer roll? i have a A in every class except in math i have a C?
ya u will make it
Reply:probably not. at my school honor roll is all As and Bs. High honors is all As.
I know, it stinks when you have all A and then a grade that will throw it off. I had all As and a D- last year. the D was in math, of course.
Reply:You even have an A in English class? "honer" is spelled h-o-n-o-r.
Reply:in my school, u have to all all a's all b's or a mix of both
Reply:yes you will . 3.0+ gets you in the honor roll i guess .
Reply:ya definitely probably distinguished honor roll if they have that at your school
Reply:You should... it would average out to a B. But it all depends on if your school goes by letter grades or averages.
Reply:Uh how the hell are we supposed to know off of that? Are you even in high school? How many classes are you talking? Is honor roll 3.0 or 3.5?
Assuming you are taking 6 classes and they are all prep classes:
4x5=20
+2
3.6 GPA
So yeah you should
22/6
marigold
Will i make honer roll? i have a A in every class except in math i have a C?
ya u will make it
Reply:probably not. at my school honor roll is all As and Bs. High honors is all As.
I know, it stinks when you have all A and then a grade that will throw it off. I had all As and a D- last year. the D was in math, of course.
Reply:You even have an A in English class? "honer" is spelled h-o-n-o-r.
Reply:in my school, u have to all all a's all b's or a mix of both
Reply:yes you will . 3.0+ gets you in the honor roll i guess .
Reply:ya definitely probably distinguished honor roll if they have that at your school
Reply:You should... it would average out to a B. But it all depends on if your school goes by letter grades or averages.
Reply:Uh how the hell are we supposed to know off of that? Are you even in high school? How many classes are you talking? Is honor roll 3.0 or 3.5?
Assuming you are taking 6 classes and they are all prep classes:
4x5=20
+2
3.6 GPA
So yeah you should
22/6
marigold
If you get a C in community college, say math and if you retake it and get an A. does the C disappear?
if you transfer only to a UC and CSU...california colleges
If you get a C in community college, say math and if you retake it and get an A. does the C disappear?
i dont think so, i think it just helps your GPA
but then again, i could be totally wrong
Reply:I don't believe that it does. Perhaps you can talk with the transfer coordinator at the college that you're currently attending or high school guidance counselor. The 'A' may bring up your gpa (grade point average) and show that you were willing to take the same course to improve your gpa though it most likely remains on your transcript. Courses and gpa's do transfer but a letter grade from a different college does not either and won't average into the gpa of the school in which one transferred to, just fyi.
US colleges: http://www.utexas.edu/world/univ
If you get a C in community college, say math and if you retake it and get an A. does the C disappear?
i dont think so, i think it just helps your GPA
but then again, i could be totally wrong
Reply:I don't believe that it does. Perhaps you can talk with the transfer coordinator at the college that you're currently attending or high school guidance counselor. The 'A' may bring up your gpa (grade point average) and show that you were willing to take the same course to improve your gpa though it most likely remains on your transcript. Courses and gpa's do transfer but a letter grade from a different college does not either and won't average into the gpa of the school in which one transferred to, just fyi.
US colleges: http://www.utexas.edu/world/univ
Write a C program to test common math functions?
For : log, exp,sin,asin,sqrt
Write a C program to test common math functions?
Seems easy enough.
Output: The square root of 4:
Then use the appropriate math function.
sqrt(4);
Output: %26lt;answer%26gt;
Do the same for the others.
Reply:all these functions are present in c library %26lt;math.h%26gt;..u can check them also u can find lots of programs and projects related to different field at %26lt;http://www.indiastudychannel.com u can also download projects from there..enjoy
Write a C program to test common math functions?
Seems easy enough.
Output: The square root of 4:
Then use the appropriate math function.
sqrt(4);
Output: %26lt;answer%26gt;
Do the same for the others.
Reply:all these functions are present in c library %26lt;math.h%26gt;..u can check them also u can find lots of programs and projects related to different field at %26lt;http://www.indiastudychannel.com u can also download projects from there..enjoy
Will someone please explain this math problem to me? -2c(2/c squared+c squared)?
I don't have to know what C is, it just has to be simplified w/ no parenthesis
Will someone please explain this math problem to me? -2c(2/c squared+c squared)?
yea all you have to do is use the the distributive property
a(a+b) = aa+ab
so
-2c(2/c^2 + c^2) = -2c/c^2 + 2c^3 it simplifies to -2^2 - 2c^3 or 4 - 2c^3
Reply:You have to distribute.
-4c/c^2 - 2c^3 The c's can be canceled in the fraction.
-4/c - 2c^3
Reply:I got something a little different . . .
. . . . . . . 2
-2c ( --------------- )
. . . . c^2 + c^2
. . . . . . 2
-2c ( ----------- ) , Cancel out the two's . . .
. . . . . 2c^2
. . . . . .1
-2c ( -------- ), now multiply the -2c . . .
. . . . c^2
-2c . . . . 1 . . . . . -2c
------ x ---- =. . . . -------
1. . . . . c^2. . . . . c^2
Reply:-2c (2/c squared + c squared)
-2c ( 4/ c^2 + c^2 ) multiply
-2c * 4/c^2 + -2c * c^2
-8/c -2 c^3
(-2c^4 - 8)/ c
Will someone please explain this math problem to me? -2c(2/c squared+c squared)?
yea all you have to do is use the the distributive property
a(a+b) = aa+ab
so
-2c(2/c^2 + c^2) = -2c/c^2 + 2c^3 it simplifies to -2^2 - 2c^3 or 4 - 2c^3
Reply:You have to distribute.
-4c/c^2 - 2c^3 The c's can be canceled in the fraction.
-4/c - 2c^3
Reply:I got something a little different . . .
. . . . . . . 2
-2c ( --------------- )
. . . . c^2 + c^2
. . . . . . 2
-2c ( ----------- ) , Cancel out the two's . . .
. . . . . 2c^2
. . . . . .1
-2c ( -------- ), now multiply the -2c . . .
. . . . c^2
-2c . . . . 1 . . . . . -2c
------ x ---- =. . . . -------
1. . . . . c^2. . . . . c^2
Reply:-2c (2/c squared + c squared)
-2c ( 4/ c^2 + c^2 ) multiply
-2c * 4/c^2 + -2c * c^2
-8/c -2 c^3
(-2c^4 - 8)/ c
If a student makes straight A's and a few B's, but C's and D's in Math, what does this mean? Are they not
not going to be able to compete in college? (High School Student) almost failing in Math.
AND THEY ARE STRUGGLING HARD TO MAKE THAT...
If a student makes straight A's and a few B's, but C's and D's in Math, what does this mean? Are they not
Your success in college depends on your major. Most people only need two math classes to graduate, like algebra and statistics.
Most teachers want their students to do well! I recommend that you ask for help from them. If you let them know that math isn't your strongest subject, they can give you study tips and other resources to boost your grades.
Don't worry about it too much. The only thing it really means is that you should stay away from a major like engineering! =D
Reply:No, no. They'll do just fine in college! That just means that they will do better in humanities than sciences. I hate math, and Physics and I got A's in them but I was always misreable studying fro them. Whereas with humanities I'd always have fun studying. I have a very high GPA now and I don't do too much effort, I simply like the stuff I'm taking. (Note to self: must seek help to reduce my titanic ego. is getting unhealthy! Cannot believe that i managed to make this about me.)
Reply:Wow. So I'm not the only one =)
I'm not kidding when I say this, I SUCK at math. I get A's for the most part, not including math, my GPA would be like a 3.9. But I've gotten my first C in AP calculus and I'm REALLY struggling. I just don't seem to grasp the concept, and the same goes for Algebra, and any type of MATH. I'm horrible at math, and I've accepted the fact that it's the way I am, because I've been like that since I was little.
Reply:It's possible that you're just not studying the right way for math or that you just don't have the right mindset for math (some people are just like that). The good news is, unless you're going to be a math, physics, or engineering major, you don't have to take much math in college.
Talk to teachers, and friends who are good at math, maybe they can explain in a different way that helps you understand better.
Reply:Well,
Knowone is terrible at a subject but it just means you should try harder and ask after school for help from a teacher, or even during class, well good luck.
Hope i helped good luck!!!
Reply:Depending on what math class you're flunking, this may not mean anything predictive about your success in college, as far as passing and getting a B.A.. Many colleges only require one class in basic math in order to complete the general education requirements. If you're seriously concerned that you won't make it through college, then when it comes time to choose between colleges, (among other things) read up on each college's general education requirements in their catalog and see if you will ever need more than one very basic course in math in the entire time you're attending that college. Personally, however, I found that taking a math-anxiety workshop at my local community college dramatically increased my math grades! Please consider seeking out resources on how to more effectively get through math classes (although of course, you could be doing badly for many reasons, including bad teaching or text, but most of my A-level students tend to do well despite bad teachers or texts, which suggests the possibility of a learning disability or anxiety instead).
Can you clarify which math class you're doing badly in, algebra? geometry? trig?
Reply:Depends on what you major in. You could always improve, I wouldn't stress over something like that and let you stay away from college.
Reply:thats terrible
dracaena
AND THEY ARE STRUGGLING HARD TO MAKE THAT...
If a student makes straight A's and a few B's, but C's and D's in Math, what does this mean? Are they not
Your success in college depends on your major. Most people only need two math classes to graduate, like algebra and statistics.
Most teachers want their students to do well! I recommend that you ask for help from them. If you let them know that math isn't your strongest subject, they can give you study tips and other resources to boost your grades.
Don't worry about it too much. The only thing it really means is that you should stay away from a major like engineering! =D
Reply:No, no. They'll do just fine in college! That just means that they will do better in humanities than sciences. I hate math, and Physics and I got A's in them but I was always misreable studying fro them. Whereas with humanities I'd always have fun studying. I have a very high GPA now and I don't do too much effort, I simply like the stuff I'm taking. (Note to self: must seek help to reduce my titanic ego. is getting unhealthy! Cannot believe that i managed to make this about me.)
Reply:Wow. So I'm not the only one =)
I'm not kidding when I say this, I SUCK at math. I get A's for the most part, not including math, my GPA would be like a 3.9. But I've gotten my first C in AP calculus and I'm REALLY struggling. I just don't seem to grasp the concept, and the same goes for Algebra, and any type of MATH. I'm horrible at math, and I've accepted the fact that it's the way I am, because I've been like that since I was little.
Reply:It's possible that you're just not studying the right way for math or that you just don't have the right mindset for math (some people are just like that). The good news is, unless you're going to be a math, physics, or engineering major, you don't have to take much math in college.
Talk to teachers, and friends who are good at math, maybe they can explain in a different way that helps you understand better.
Reply:Well,
Knowone is terrible at a subject but it just means you should try harder and ask after school for help from a teacher, or even during class, well good luck.
Hope i helped good luck!!!
Reply:Depending on what math class you're flunking, this may not mean anything predictive about your success in college, as far as passing and getting a B.A.. Many colleges only require one class in basic math in order to complete the general education requirements. If you're seriously concerned that you won't make it through college, then when it comes time to choose between colleges, (among other things) read up on each college's general education requirements in their catalog and see if you will ever need more than one very basic course in math in the entire time you're attending that college. Personally, however, I found that taking a math-anxiety workshop at my local community college dramatically increased my math grades! Please consider seeking out resources on how to more effectively get through math classes (although of course, you could be doing badly for many reasons, including bad teaching or text, but most of my A-level students tend to do well despite bad teachers or texts, which suggests the possibility of a learning disability or anxiety instead).
Can you clarify which math class you're doing badly in, algebra? geometry? trig?
Reply:Depends on what you major in. You could always improve, I wouldn't stress over something like that and let you stay away from college.
Reply:thats terrible
dracaena
IF anyone knows this, please help....Math...(solve for a, b, and c)????
a + b + c + ab + bc + ac = abc + 1
Solve for variables a, b, and c such that a, b, and c are positive integers where a%26lt;=b%26lt;=c.
Find all a, b, and c values that fit the equation.
Thanks Very Very Very Much...
IF anyone knows this, please help....Math...(solve for a, b, and c)????
Matlab program:
function gett()
lim = 1000;
for a=0:lim
for b=a:lim
for c=b:lim
if a + b + c + a*b + b*c + a*c == a*b*c + 1
[a b c]
end
end
end
end
Result:
a=0, b=0, c=1
a=2, b=4, c=13
a=2, b= 5, c=8
a=3, b=3, c=7
* * * * * * * * *
lim= 1000 is sufficient because
a*b*c = 1000,000,000
which will always be greater than small numbers of ab + bc + ac.....
So, as numbers increase there will be no solutions.
==%26gt; Only 4 solutions (see above)
Reply:i think i got it : if you want each variable to be different then try this:
a needs to be a negative number
b needs to be number 1
c needs to be a positive number of a
so try this
a=-2
b=1
c=2
plug in and you get
-3=-3
Solve for variables a, b, and c such that a, b, and c are positive integers where a%26lt;=b%26lt;=c.
Find all a, b, and c values that fit the equation.
Thanks Very Very Very Much...
IF anyone knows this, please help....Math...(solve for a, b, and c)????
Matlab program:
function gett()
lim = 1000;
for a=0:lim
for b=a:lim
for c=b:lim
if a + b + c + a*b + b*c + a*c == a*b*c + 1
[a b c]
end
end
end
end
Result:
a=0, b=0, c=1
a=2, b=4, c=13
a=2, b= 5, c=8
a=3, b=3, c=7
* * * * * * * * *
lim= 1000 is sufficient because
a*b*c = 1000,000,000
which will always be greater than small numbers of ab + bc + ac.....
So, as numbers increase there will be no solutions.
==%26gt; Only 4 solutions (see above)
Reply:i think i got it : if you want each variable to be different then try this:
a needs to be a negative number
b needs to be number 1
c needs to be a positive number of a
so try this
a=-2
b=1
c=2
plug in and you get
-3=-3
Quick 10 points! answer this easy math problem, see details!! c'mon everyone!!?
Ok you must follow these guidelines:
add arithmatical symbols on the left of the equal sign in between the numbers to make this equation true. Make 100=100. You cant use a number twice. A symbol (+, -, x) must be placed in between every number.
1 2 3 4 5 6 7 8 9 = 100
off you go!
Quick 10 points! answer this easy math problem, see details!! c'mon everyone!!?
1+2+3+4+5+6+7+8x9 = 100
Reply:Got there in the end, its like countdown!
1+2+3+4+5+6+7+8x9 = 100
Reply:9x8+7+6+5+4+3+2+1=100
72+11+7+3+7=100
83+10+7=100
93+7=100
100=100
so here's your answer!!!
Reply:1+2+3+4+5+6+7+(9x8)=100
72+28=100
100=100
but it needs a minus sign... (+ ,- x)
so...
[(9x7)+(6x3)+8+5+4+3+1]-2=100
[63+18+8+5+4+3+1]-2=100
[102]-2=100
100=100
yey!
morning glory
add arithmatical symbols on the left of the equal sign in between the numbers to make this equation true. Make 100=100. You cant use a number twice. A symbol (+, -, x) must be placed in between every number.
1 2 3 4 5 6 7 8 9 = 100
off you go!
Quick 10 points! answer this easy math problem, see details!! c'mon everyone!!?
1+2+3+4+5+6+7+8x9 = 100
Reply:Got there in the end, its like countdown!
1+2+3+4+5+6+7+8x9 = 100
Reply:9x8+7+6+5+4+3+2+1=100
72+11+7+3+7=100
83+10+7=100
93+7=100
100=100
so here's your answer!!!
Reply:1+2+3+4+5+6+7+(9x8)=100
72+28=100
100=100
but it needs a minus sign... (+ ,- x)
so...
[(9x7)+(6x3)+8+5+4+3+1]-2=100
[63+18+8+5+4+3+1]-2=100
[102]-2=100
100=100
yey!
morning glory
Sunday, July 12, 2009
Can you help me in this math problem? (2a+3b+c+2d+e) raised to the second power?
Can you solve it?
Can you help me in this math problem? (2a+3b+c+2d+e) raised to the second power?
Lets see...hmmm.....2+3+2=7 %26amp; a+b+c+d+e = abcde...so 7abcde to the power of 2? = 49abcde!...lol
Reply:Ok, I'm a chemist nerd, not a math nerd, but I believe that the entire parenthetical expression must be multiplied by itself. Start this baby slow, first multiply 2a by the whole expression, so 4a^2+6ab+2ac+4da+2e, do this until everything in the parenthesis has been multiplied by everything else. Then add like terms.
Try it on your own by my method above before reading on...
go on...
try it...
Ok, this is what I calculated:
4a^2+12ab+4ac+8ad+4ae+9b^2+6bc
+12bd+6be+c^2+4cd+2ce+4d^2+4de
+e^2 (good lord)
This is probally a homework problem, so learn the method before the test.
Reply:(2a + 3b + c + 2d + e)²
4a² + 9b² + c² + 4d² + e²
Reply:Ah pentanomail theorem. I did it the hard way and so:
4a^2 + 12ab + 4ac +8ad + 4ae + 9b^2 + 6bc + 12bd + 6be + 4cd + 2ce + 4d^2 +4de + e^2.
http://i51.photobucket.com/albums/f354/l...
all the work
Reply:Call your math teacher
Reply:You take teh power and simply attach it to your variables. this makes it 2a2+3b2+c2+2d2+e2 the second 2's are exponents.
Reply:I disagree with everyone so far. I get (4a^2+9b^2+c^2+4d^2+e^2) (F.Y.I. ^ is the symbol for exponents)
Reply:multiply it with the original equation
Reply:(2a+3b+c+2d+e) 2 = 4a2+9b2 +c2+4d2+e2
Reply:(2a+3b+c+2d+e)^2 = ?
Answer: 4a^2+9b^2+4d^2+c^2+4d^2+e^2.
Simplifying:
(2a)^2 + (3b)^2 + (2d)^2 + c^2 + (2d)^2 + e^2 =
4a^2+9b^2+4d^2+c^2+4d^2+e^2.
Please note: ^ represents exponent.
Can you help me in this math problem? (2a+3b+c+2d+e) raised to the second power?
Lets see...hmmm.....2+3+2=7 %26amp; a+b+c+d+e = abcde...so 7abcde to the power of 2? = 49abcde!...lol
Reply:Ok, I'm a chemist nerd, not a math nerd, but I believe that the entire parenthetical expression must be multiplied by itself. Start this baby slow, first multiply 2a by the whole expression, so 4a^2+6ab+2ac+4da+2e, do this until everything in the parenthesis has been multiplied by everything else. Then add like terms.
Try it on your own by my method above before reading on...
go on...
try it...
Ok, this is what I calculated:
4a^2+12ab+4ac+8ad+4ae+9b^2+6bc
+12bd+6be+c^2+4cd+2ce+4d^2+4de
+e^2 (good lord)
This is probally a homework problem, so learn the method before the test.
Reply:(2a + 3b + c + 2d + e)²
4a² + 9b² + c² + 4d² + e²
Reply:Ah pentanomail theorem. I did it the hard way and so:
4a^2 + 12ab + 4ac +8ad + 4ae + 9b^2 + 6bc + 12bd + 6be + 4cd + 2ce + 4d^2 +4de + e^2.
http://i51.photobucket.com/albums/f354/l...
all the work
Reply:Call your math teacher
Reply:You take teh power and simply attach it to your variables. this makes it 2a2+3b2+c2+2d2+e2 the second 2's are exponents.
Reply:I disagree with everyone so far. I get (4a^2+9b^2+c^2+4d^2+e^2) (F.Y.I. ^ is the symbol for exponents)
Reply:multiply it with the original equation
Reply:(2a+3b+c+2d+e) 2 = 4a2+9b2 +c2+4d2+e2
Reply:(2a+3b+c+2d+e)^2 = ?
Answer: 4a^2+9b^2+4d^2+c^2+4d^2+e^2.
Simplifying:
(2a)^2 + (3b)^2 + (2d)^2 + c^2 + (2d)^2 + e^2 =
4a^2+9b^2+4d^2+c^2+4d^2+e^2.
Please note: ^ represents exponent.
Derive a math expression for converting between degrees C and degrees A? Please look at details for more info.
Ethylene glycol is the main component in car antifreeze. To monitor the temperature of an auto cooling system you decide to develop a new temperature scale that reads from 0 to 100. Your new thermometer scale is vased on the melting and boiling points of antifreeze solution (-45 degrees C and 115 degrees C) and you want these correspond to 0 degrees A and 100 degrees A, respectively. Please tell me how you derive to the answer, not just the answer
Derive a math expression for converting between degrees C and degrees A? Please look at details for more info.
The range -45 C to +115 C is 160 degrees celcius, therefore the ratio of C to A is 1.6 to 1. Given that the A scale starts at zero and the bottom of the C range starts at -45, you'll need to offset any C numbers by +45 to avoid any negative A numbers. This means that if you take any C value, add 45 to it and divide by 1.6, you'll get the equivalent A value.
So, the expression is A=(C+45)/1.6
Let's try it out:
If C is -45, A is (-45+45)/1.6 = 0
If C is 115, A is (115+45)/1.6=100
If C is 0, A is (0+45)/1.6=28.125
Reply:scale A 0 to 100 is equivalent to -45 to 115 deg C
100 units on A = 160 units on C
deg A = (deg C+45)/1.6 = 0.625(deg C + 45) = 5/8 (deg C + 45)
deg C = 8/5 (deg A) -45
Reply:Oh shhit im soo bad in maths.
Reply:from -45 to 115 = 160 100 for Celsius
so there are 8/5 as ,many degrees in A
A=8/5C-45
C=5/8(45+A)
Derive a math expression for converting between degrees C and degrees A? Please look at details for more info.
The range -45 C to +115 C is 160 degrees celcius, therefore the ratio of C to A is 1.6 to 1. Given that the A scale starts at zero and the bottom of the C range starts at -45, you'll need to offset any C numbers by +45 to avoid any negative A numbers. This means that if you take any C value, add 45 to it and divide by 1.6, you'll get the equivalent A value.
So, the expression is A=(C+45)/1.6
Let's try it out:
If C is -45, A is (-45+45)/1.6 = 0
If C is 115, A is (115+45)/1.6=100
If C is 0, A is (0+45)/1.6=28.125
Reply:scale A 0 to 100 is equivalent to -45 to 115 deg C
100 units on A = 160 units on C
deg A = (deg C+45)/1.6 = 0.625(deg C + 45) = 5/8 (deg C + 45)
deg C = 8/5 (deg A) -45
Reply:Oh shhit im soo bad in maths.
Reply:from -45 to 115 = 160 100 for Celsius
so there are 8/5 as ,many degrees in A
A=8/5C-45
C=5/8(45+A)
I have a question about programming in ti basic b/c i have an assignment in math to make a game.?
I would like some help b/c i dont know how to get a randomly assigned number to get into the getkey code, meaning the different letters and numbers need to "fall" from the top of the ti 84 screen. i know how to make the random number to generate, using the randInt(x,y) function. but how do i get that number into the program to make the assigned letter or number "fall"? thank you for your time in helping me
I have a question about programming in ti basic b/c i have an assignment in math to make a game.?
you can use the randInt(x,y) [and any other function you can type in the normal input screen] in your programs.
Reply:This sounds like a really old version of basic. I'd ask the teacher.
I have a question about programming in ti basic b/c i have an assignment in math to make a game.?
you can use the randInt(x,y) [and any other function you can type in the normal input screen] in your programs.
Reply:This sounds like a really old version of basic. I'd ask the teacher.
How can I use the Math.Max method in c# to compare 6 numbers?
I also need to find the minimum as well.
How can I use the Math.Max method in c# to compare 6 numbers?
Nested looping
Put the values in an array
Use the array index value as the looping control value, e.g.
the outer loop goes from i=0 to 4 while the inner loop goes from
j=i+1 to 5 (array indices start at zero, right?)
Compare the values in the array positions i and j using the max function.
You can store the max and min found after the comparisons.
Change the stored max only if the new max is greater than the one you have stored.
Change the stored min only if the new min is less than the one you have stored.
And no, I won't write it for you - but good luck! :)
--------------------------------
Doesn't matter how you get the values... you can still save and compare them. An array is just for simplicity's sake. If you haven't done arrays yet, then just store them in variables a1, b2, c3, d4, e5, and f6 (as examples). Store your overall max in max_all, store your overall min in min_all. Compare them all sequentially if you need to.
The max(a1,b2) function will give you back the larger of the two values. The max(a1, max_all) result will tell you if you should replace your stored max with the one you just got back from comparing the first two.
Nest them all if you want:
max_all = max(a1,max(b2,max(c3, max(d4, max(e5, f6)))))
Heck, now I'm writing code ;-)
Still, good luck.
geranium
How can I use the Math.Max method in c# to compare 6 numbers?
Nested looping
Put the values in an array
Use the array index value as the looping control value, e.g.
the outer loop goes from i=0 to 4 while the inner loop goes from
j=i+1 to 5 (array indices start at zero, right?)
Compare the values in the array positions i and j using the max function.
You can store the max and min found after the comparisons.
Change the stored max only if the new max is greater than the one you have stored.
Change the stored min only if the new min is less than the one you have stored.
And no, I won't write it for you - but good luck! :)
--------------------------------
Doesn't matter how you get the values... you can still save and compare them. An array is just for simplicity's sake. If you haven't done arrays yet, then just store them in variables a1, b2, c3, d4, e5, and f6 (as examples). Store your overall max in max_all, store your overall min in min_all. Compare them all sequentially if you need to.
The max(a1,b2) function will give you back the larger of the two values. The max(a1, max_all) result will tell you if you should replace your stored max with the one you just got back from comparing the first two.
Nest them all if you want:
max_all = max(a1,max(b2,max(c3, max(d4, max(e5, f6)))))
Heck, now I'm writing code ;-)
Still, good luck.
geranium
Math: If logb5=a, logb2.5=c, and 5^x=2.5, then x=?
If logb5=a, logb2.5=c, and 5^x=2.5, then x=?
Math: If logb5=a, logb2.5=c, and 5^x=2.5, then x=?
logb5=a
logb2.5=c
5^x=2.5
(logb both side)
logb5^x=logb2.5
x logb5 = logb2.5 (b is any number, i prefer 10)
x = log2.5/log5 = 0.569...
(i think it's 'computer says')
Reply:The equation you have to solve is
5^x = 2.5
and the way to proceed is to take logarithms of both sides :
x * log 5 = log 2.5
so x = log 2.5 / log 5
and it does not matter what base you use for the logarithms - you could use 2, or 10, or e or anything that takes your fancy.
However, since you are given these two logarithms to some unknown base, b, then I presume that you are meant to give the answer in terms of those given logarithms, therefore
x = c / a
Reply:computer says x=log5(2.5)=logb2.5/logb5=c/a..use log base conv rule..
Math: If logb5=a, logb2.5=c, and 5^x=2.5, then x=?
logb5=a
logb2.5=c
5^x=2.5
(logb both side)
logb5^x=logb2.5
x logb5 = logb2.5 (b is any number, i prefer 10)
x = log2.5/log5 = 0.569...
(i think it's 'computer says')
Reply:The equation you have to solve is
5^x = 2.5
and the way to proceed is to take logarithms of both sides :
x * log 5 = log 2.5
so x = log 2.5 / log 5
and it does not matter what base you use for the logarithms - you could use 2, or 10, or e or anything that takes your fancy.
However, since you are given these two logarithms to some unknown base, b, then I presume that you are meant to give the answer in terms of those given logarithms, therefore
x = c / a
Reply:computer says x=log5(2.5)=logb2.5/logb5=c/a..use log base conv rule..
Thanks everyone, I know how to figure interest, J C you were right, details below. Math not my thing?
I bought 12.20 acres for 30,000. The payment was 284.78 per month. The interest is calculated at 7.240% per annum. on a 15 year mortgage. After 4 years I've paid nearly 14,484.. and still owe 27,000. Thank you all, math certainly isn't my thing.
Thanks everyone, I know how to figure interest, J C you were right, details below. Math not my thing?
Excel has a very friendly formula to calculate payments and interest.
It is PMT. Play with it and you will find how to draw the table of payments and how much of every payment is interest and how much is principal. In general terms what happens is that the first payment you are paying almost only interest and in the last payment you pay only principal. The proportion changes a little with every payment. After year 7 you´ll be much happier. Hope it helps.
Thanks everyone, I know how to figure interest, J C you were right, details below. Math not my thing?
Excel has a very friendly formula to calculate payments and interest.
It is PMT. Play with it and you will find how to draw the table of payments and how much of every payment is interest and how much is principal. In general terms what happens is that the first payment you are paying almost only interest and in the last payment you pay only principal. The proportion changes a little with every payment. After year 7 you´ll be much happier. Hope it helps.
Oh great! I hate math and got a C+ what can i Do?
Haha, regardless of what other people say, you and I both know that you will NEVER find maths fun/interesting.
So know you face two options: Tutor or study harder.
Personally a tutor will probably always be the best option...for those who can afford it. Otherwise get a study-group together, ask your smart friends for help and ask them to tell you in the simpliest terms how to do stuff.
If all else fails cheat of the person beside you! :P
Oh great! I hate math and got a C+ what can i Do?
Study. Do your homework. Ask the teacher what you can do to make it up.
Reply:Avoid unnecessary distractions and interruptions.
Cultivate concentration.
Keep the mind alert.
Develop self-confidence.
Practice critical thinking.
Pcoceed systematically and thouruoghly.
Analyce difficulties.
Learn accurately the fundamentals.
Clarify thought by writing.
Veryfy results.
If you follow the above tips, it will surely lead to success
SOURCE
http://math-homeworkhelp.blogspot.com/
Reply:First of all, you won't do well if you hate it. Get ET Bell's
"Men of Mathematics," biographies of really interesting men who were mathematicians, like Henri Poincare, a mathematician and President of France!
Here is good help. This is a jump page with links to may sites, look at a few a day:
http://www.khake.com/page47
a pro math site:
http://www.mathworld.wolfram.com
How to study math:
http://www.utexas.edu/student/utlc/lrnre...
http://www.mathweb.com
http://mathforum.org/library/topics/prob...
Martin Gardner has written much interesting material about math!
Contact me on here if you need more help!! Look at the khake site carefully - the is help for other subjects there to - and employment help!
Get a good paperback math dictionary!
http://www.flashcardexchange.com print your own flash cards from an extensive library!!
I once failed algebra, but later passed differential equations - don't quit and always ask for help.
Print this out and give it to your friends and your teacher!! I hope that you keep trying - you will get better jobs and meet more interesting people!! I worked in the chemical industry (perfume reasearch) and as a journeyman electrician - both take math!!
Reply:I think that's pretty good for someone who hate Math. I loved Forensic Science but I got a D lol.
Reply:Try to love it
Reply:Study more. If you already "hate" it you'll have ongoing problems until you get over it. Most math is mechanical reproduction of whatever idea is being presented, applied to specific items of information disclosed. If you learn the concept first you'll have an easier time of it. If I can help let me know. I try not to give away the answer but instead teach the theory behind getting to the answer. Your brain CAN handle it, even though if you learn enough it counts as rocket science. ;-)
I like word finds and Sudoku puzzles, and searching for the right answers. Think of it as a game. You'll use math your whole life, might as well get to like it.
Reply:try to like it.its very interesting.....which grade r u in?
Reply:get a tutor or study harder.
Reply:Study harder next time and talk to your teacher/professor about what you did wrong and how you can improve your performance in the future.
Reply:You mean you want an even lower grade ?
Reply:find a fun ways to study make up your own game
Reply:up and down for joy
Reply:first make up your mind to love maathsthen it bcomes far more interesting.also if u feel ur proff to b boring talk to him privately.
u can also go in for interesting puzzles and other things 2 make the subject interesting
best of luck
Reply:try harder
Reply:Extra credit like "Sasha" does. She posted about 30 extra credit problems here and probably will pass the 8th grade because of it.
So know you face two options: Tutor or study harder.
Personally a tutor will probably always be the best option...for those who can afford it. Otherwise get a study-group together, ask your smart friends for help and ask them to tell you in the simpliest terms how to do stuff.
If all else fails cheat of the person beside you! :P
Oh great! I hate math and got a C+ what can i Do?
Study. Do your homework. Ask the teacher what you can do to make it up.
Reply:Avoid unnecessary distractions and interruptions.
Cultivate concentration.
Keep the mind alert.
Develop self-confidence.
Practice critical thinking.
Pcoceed systematically and thouruoghly.
Analyce difficulties.
Learn accurately the fundamentals.
Clarify thought by writing.
Veryfy results.
If you follow the above tips, it will surely lead to success
SOURCE
http://math-homeworkhelp.blogspot.com/
Reply:First of all, you won't do well if you hate it. Get ET Bell's
"Men of Mathematics," biographies of really interesting men who were mathematicians, like Henri Poincare, a mathematician and President of France!
Here is good help. This is a jump page with links to may sites, look at a few a day:
http://www.khake.com/page47
a pro math site:
http://www.mathworld.wolfram.com
How to study math:
http://www.utexas.edu/student/utlc/lrnre...
http://www.mathweb.com
http://mathforum.org/library/topics/prob...
Martin Gardner has written much interesting material about math!
Contact me on here if you need more help!! Look at the khake site carefully - the is help for other subjects there to - and employment help!
Get a good paperback math dictionary!
http://www.flashcardexchange.com print your own flash cards from an extensive library!!
I once failed algebra, but later passed differential equations - don't quit and always ask for help.
Print this out and give it to your friends and your teacher!! I hope that you keep trying - you will get better jobs and meet more interesting people!! I worked in the chemical industry (perfume reasearch) and as a journeyman electrician - both take math!!
Reply:I think that's pretty good for someone who hate Math. I loved Forensic Science but I got a D lol.
Reply:Try to love it
Reply:Study more. If you already "hate" it you'll have ongoing problems until you get over it. Most math is mechanical reproduction of whatever idea is being presented, applied to specific items of information disclosed. If you learn the concept first you'll have an easier time of it. If I can help let me know. I try not to give away the answer but instead teach the theory behind getting to the answer. Your brain CAN handle it, even though if you learn enough it counts as rocket science. ;-)
I like word finds and Sudoku puzzles, and searching for the right answers. Think of it as a game. You'll use math your whole life, might as well get to like it.
Reply:try to like it.its very interesting.....which grade r u in?
Reply:get a tutor or study harder.
Reply:Study harder next time and talk to your teacher/professor about what you did wrong and how you can improve your performance in the future.
Reply:You mean you want an even lower grade ?
Reply:find a fun ways to study make up your own game
Reply:up and down for joy
Reply:first make up your mind to love maathsthen it bcomes far more interesting.also if u feel ur proff to b boring talk to him privately.
u can also go in for interesting puzzles and other things 2 make the subject interesting
best of luck
Reply:try harder
Reply:Extra credit like "Sasha" does. She posted about 30 extra credit problems here and probably will pass the 8th grade because of it.
Is a 78 in math a a,b,c,or d ?¿?
i need to know because i dont know ...............
Is a 78 in math a a,b,c,or d ?¿?
It depends on your school, but usually a 78 is a grade "C".
90-100 A
80-89 B
70-79 C
60-69 D
Below 60 F
Sometimes below a 66 is an F...
Reply:at my school, 78 is a C average... a 72 is a D
Reply:it depends on the point grading scale your teacher uses. on a 10 point scale, it would be a C+ on a 7 pt scale like my high school used, it would be a D. so check with your teacher to be sure.
Reply:Its a C+
Reply:a 78 would be a C+ a 75 would be just a C and an 80 would be a B
sweet pea
Is a 78 in math a a,b,c,or d ?¿?
It depends on your school, but usually a 78 is a grade "C".
90-100 A
80-89 B
70-79 C
60-69 D
Below 60 F
Sometimes below a 66 is an F...
Reply:at my school, 78 is a C average... a 72 is a D
Reply:it depends on the point grading scale your teacher uses. on a 10 point scale, it would be a C+ on a 7 pt scale like my high school used, it would be a D. so check with your teacher to be sure.
Reply:Its a C+
Reply:a 78 would be a C+ a 75 would be just a C and an 80 would be a B
sweet pea
Whatis the math answer to 20 +c = 4c -7?
20 + c = 4c - 7
27+ c = 4c
27 = 3c
c = 27/3
c = 9
Whatis the math answer to 20 +c = 4c -7?
20+c=4c-7
27+c=4c
27=3c
27/3=9
c=9
Reply:The answer is:
group all of the like components together and figure it out. If you don't understand what grouping all of the like components together means, the answer is this: go to your teacher and ask for extra help. It's one thing for someone to hand you the answer here, and it's another entirely to be caught out on the test when you have no idea how to do it for youself. Trust me, you are doing yourself a favour by learning to do it yourself.
Reply:20 + c = 4c - 7
+7 - c= -c + 7
___________
27 + 0= 3c + 0
becomes 27=3c, then divide by 3
27=3c
--- ---
3 * 3
27=c
---
3
c=9
the * represents a space so that you didn't think i was dividing by 33, bc i wasn't :)
Reply:c=9 ...
20=4c-c-7
20=3c-7
27=3c
27/3=c
9=c
Reply:c=9
Reply:If you are trying to find the value of c, the answer is 9. This is how you solve:
1. Add 7 to both sides of the equation, which will yield:
27+c=4c
2. Then subtract c (which is actually 1c) from both sides, resulting in: 27=3c
3. Divide each side by 3, and you will isolate c. The result is 9.
4. Check if your answer is correct by plugging in "9" in place of "c" in the original equation:
Does 20 + 9 equal 4 (9) - 7? YES!
Reply:the answer would be 9=C
because you can only have C on one side and numbers on the other.
So this is how it would go:
20+c=4c-7
-c -c
= 20=3c-7
+7 +7
= 27=3c
divide by 3 and you get 9=c
=]
Reply:move the c over to the right by subtracting it and move the 7 over by adding to 20. You'll get 27=3c. divide by 3 and you've got your answer.
Reply:20 +7 = 4c - c
27 = 3c
c = 27/3
c=9
Reply:the answer is 9. add 7 to 20 to get 27. Subtract c from 4c to get 3c. Then divide 27 by 3 and you get c = 3. It's called combining like terms.
Reply:9
Reply:You solve something like this the exact same way you would solve something like ... x + 10 = 12. If you subtract 10 from each side of the equation, you end up with x = 2. Just remember that whatever you do to one side of the equation, you must do to the other. You want to get the variable on one side by itself. Try adding 7 to both sides of the equation and subtracting c from each side of the equation...
Reply:6.75
Reply:20+c=4c-7
subtract 1c off each side leaving 20=3c-7
then add seven to each side leaving 27=3c
then divide each side by 3 which leaves 9=c
Reply:27=3c
27 divided by 3 = c
c=9
27+ c = 4c
27 = 3c
c = 27/3
c = 9
Whatis the math answer to 20 +c = 4c -7?
20+c=4c-7
27+c=4c
27=3c
27/3=9
c=9
Reply:The answer is:
group all of the like components together and figure it out. If you don't understand what grouping all of the like components together means, the answer is this: go to your teacher and ask for extra help. It's one thing for someone to hand you the answer here, and it's another entirely to be caught out on the test when you have no idea how to do it for youself. Trust me, you are doing yourself a favour by learning to do it yourself.
Reply:20 + c = 4c - 7
+7 - c= -c + 7
___________
27 + 0= 3c + 0
becomes 27=3c, then divide by 3
27=3c
--- ---
3 * 3
27=c
---
3
c=9
the * represents a space so that you didn't think i was dividing by 33, bc i wasn't :)
Reply:c=9 ...
20=4c-c-7
20=3c-7
27=3c
27/3=c
9=c
Reply:c=9
Reply:If you are trying to find the value of c, the answer is 9. This is how you solve:
1. Add 7 to both sides of the equation, which will yield:
27+c=4c
2. Then subtract c (which is actually 1c) from both sides, resulting in: 27=3c
3. Divide each side by 3, and you will isolate c. The result is 9.
4. Check if your answer is correct by plugging in "9" in place of "c" in the original equation:
Does 20 + 9 equal 4 (9) - 7? YES!
Reply:the answer would be 9=C
because you can only have C on one side and numbers on the other.
So this is how it would go:
20+c=4c-7
-c -c
= 20=3c-7
+7 +7
= 27=3c
divide by 3 and you get 9=c
=]
Reply:move the c over to the right by subtracting it and move the 7 over by adding to 20. You'll get 27=3c. divide by 3 and you've got your answer.
Reply:20 +7 = 4c - c
27 = 3c
c = 27/3
c=9
Reply:the answer is 9. add 7 to 20 to get 27. Subtract c from 4c to get 3c. Then divide 27 by 3 and you get c = 3. It's called combining like terms.
Reply:9
Reply:You solve something like this the exact same way you would solve something like ... x + 10 = 12. If you subtract 10 from each side of the equation, you end up with x = 2. Just remember that whatever you do to one side of the equation, you must do to the other. You want to get the variable on one side by itself. Try adding 7 to both sides of the equation and subtracting c from each side of the equation...
Reply:6.75
Reply:20+c=4c-7
subtract 1c off each side leaving 20=3c-7
then add seven to each side leaving 27=3c
then divide each side by 3 which leaves 9=c
Reply:27=3c
27 divided by 3 = c
c=9
Math homework Ax+By=C?
how do i find a perpendicular line across fromk this on containing certain points
Math homework Ax+By=C?
well you always want to put it into slope intercept form which is y= mx+b
so you would take your equation and solve for y
Ax+By = C
By= -Ax+C
y = -A/Bx+C/B
your slope is m so the number in fornt of the x is your slope
to find a perpendicular line to this line you take your slope and turn it into the a negative reciprical. so that means turn the fraction upside down and if its positive turn it into a negative and if its a negative turn it into a positive
so your perpendicalr line to this would have a slope of +B/A
now to find the line you plug in one of those points you have and the slope into this formula
y-ysub1=m(x-xsub1)
ysub1 and xsub1 are the x and y points on one of the points and m is the slope and then just solve for y
Math homework Ax+By=C?
well you always want to put it into slope intercept form which is y= mx+b
so you would take your equation and solve for y
Ax+By = C
By= -Ax+C
y = -A/Bx+C/B
your slope is m so the number in fornt of the x is your slope
to find a perpendicular line to this line you take your slope and turn it into the a negative reciprical. so that means turn the fraction upside down and if its positive turn it into a negative and if its a negative turn it into a positive
so your perpendicalr line to this would have a slope of +B/A
now to find the line you plug in one of those points you have and the slope into this formula
y-ysub1=m(x-xsub1)
ysub1 and xsub1 are the x and y points on one of the points and m is the slope and then just solve for y
How do programmers use math to create stuff. I know C++ and I am good at Math and I can't find ways to put
it all together. DO they programmers think first on paper with math. Please help me. Just show me how they can be combine. Thank u
How do programmers use math to create stuff. I know C++ and I am good at Math and I can't find ways to put
you need to use and exercise creative powers
and innovative thinking.
Reply:You must know the algorithm of a problem.
Reply:In order to put your math skills to work, you must first identify what you would like to accomplish. Remember, programming is done with a purpose, not simply because there is nothing else to do. For instance, you might want to create software to run simulations (e.g. DNA folding, like the folding@home project). You would then identify the process by which such folding takes place. Mathematically, you devise how to perform the necessary calculations. Then you translate those into programmatic functions in a way that is most efficient for a computer to use. So in the end, it depends on what you would like to accomplish--you simply can't apply skills without a goal.
If you're asking for something you can try doing realistically, an old problem that mathematically inclined programmers like to tackle is a prime number generator. This seems like an easy task at first, but making one that works very fast is a great challenge. Try it out. To get you started, here's a horribly inefficient prime number function I made in my first C++ class:
int primeNumberOutput(int params[])
{
int counter = 2,
counter2 = 1,
innerCounter,
primeNumbersCounter = 0,
primeNumbersSum = 0,
primeNumbersExpected = params[0],
factors,
columns = params[1],
columnsWidth = params[2];
do
{
factors = 0;
innerCounter = 1;
do
{
// determines how many factors counter has
if (counter % innerCounter == 0)
factors++;
innerCounter++;
}
while (innerCounter %26lt;= counter);
// following condition determines if a number is prime
if (factors %26lt;= 2)
{
primeNumbersCounter++;
primeNumbersSum += counter;
cout %26lt;%26lt; setw(columnsWidth) %26lt;%26lt; counter;
// next two conditions format the output
if (primeNumbersCounter %26lt; primeNumbersExpected)
cout %26lt;%26lt; ", ";
if (counter2 % columns == 0 %26amp;%26amp;
primeNumbersCounter %26lt; primeNumbersExpected)
cout %26lt;%26lt; endl;
counter2++;
}
counter++;
}
while (primeNumbersCounter %26lt; primeNumbersExpected);
return primeNumbersSum;
}
See if you can improve upon it's design to make it work more efficiently.
Reply:they have to think about the logic of the programs. Most logics involve maths. for examples you need maths to iterate through a list to get the data you might want. so most programmers work out the logic flow on paper first before they start the actually coding on the computer.
Reply:Logic is required for solving any problem.
In the process of deciding the flow of the program u decide the logic and then put that flow in your program.
It'll come by little practice. Make 10 programs by yourself and u'll find everything falling in place.
Reply:I read a book about famous hackers (good sense hackers) like Linus Torvalds and he said that he doesn't usually write out things on paper. But that's just him. Whatever works for you to organize your ideas. You need to develop your own style.
How do programmers use math to create stuff. I know C++ and I am good at Math and I can't find ways to put
you need to use and exercise creative powers
and innovative thinking.
Reply:You must know the algorithm of a problem.
Reply:In order to put your math skills to work, you must first identify what you would like to accomplish. Remember, programming is done with a purpose, not simply because there is nothing else to do. For instance, you might want to create software to run simulations (e.g. DNA folding, like the folding@home project). You would then identify the process by which such folding takes place. Mathematically, you devise how to perform the necessary calculations. Then you translate those into programmatic functions in a way that is most efficient for a computer to use. So in the end, it depends on what you would like to accomplish--you simply can't apply skills without a goal.
If you're asking for something you can try doing realistically, an old problem that mathematically inclined programmers like to tackle is a prime number generator. This seems like an easy task at first, but making one that works very fast is a great challenge. Try it out. To get you started, here's a horribly inefficient prime number function I made in my first C++ class:
int primeNumberOutput(int params[])
{
int counter = 2,
counter2 = 1,
innerCounter,
primeNumbersCounter = 0,
primeNumbersSum = 0,
primeNumbersExpected = params[0],
factors,
columns = params[1],
columnsWidth = params[2];
do
{
factors = 0;
innerCounter = 1;
do
{
// determines how many factors counter has
if (counter % innerCounter == 0)
factors++;
innerCounter++;
}
while (innerCounter %26lt;= counter);
// following condition determines if a number is prime
if (factors %26lt;= 2)
{
primeNumbersCounter++;
primeNumbersSum += counter;
cout %26lt;%26lt; setw(columnsWidth) %26lt;%26lt; counter;
// next two conditions format the output
if (primeNumbersCounter %26lt; primeNumbersExpected)
cout %26lt;%26lt; ", ";
if (counter2 % columns == 0 %26amp;%26amp;
primeNumbersCounter %26lt; primeNumbersExpected)
cout %26lt;%26lt; endl;
counter2++;
}
counter++;
}
while (primeNumbersCounter %26lt; primeNumbersExpected);
return primeNumbersSum;
}
See if you can improve upon it's design to make it work more efficiently.
Reply:they have to think about the logic of the programs. Most logics involve maths. for examples you need maths to iterate through a list to get the data you might want. so most programmers work out the logic flow on paper first before they start the actually coding on the computer.
Reply:Logic is required for solving any problem.
In the process of deciding the flow of the program u decide the logic and then put that flow in your program.
It'll come by little practice. Make 10 programs by yourself and u'll find everything falling in place.
Reply:I read a book about famous hackers (good sense hackers) like Linus Torvalds and he said that he doesn't usually write out things on paper. But that's just him. Whatever works for you to organize your ideas. You need to develop your own style.
Hi, I wanted to know if I will fail the 7th grade this year b/c I failed my math final.?
If your overall math grade can sustain the hit of the final (meaning you still passed math), then you should probably be promoted to 8th grade.
Hi, I wanted to know if I will fail the 7th grade this year b/c I failed my math final.?
If you do there is summer school.
Reply:You probably won't fail. If you were going to fail, your teacher would have needed to already contact your parents. You would have been given a thing called an ILP, which stands for Individual Learning Plan. You might get a D though -- but that's still pasing!
Reply:Well, In my school district rules, If a student fail more than one class you'll be retain. But if you fail but one class, then u have to go to summer school for that class
Good luck
Reply:I doubt that just failing a math final will hold you back a whole grade. It depends on how good or bad your other course grades are and your schools policies. Perhaps you'll have to attend summer school or if your grades in math were already high enough then the failing grade will still factor in as a passing grade. Don't worry.
Reply:depends on where you live and what school you go to
In my town you would have but they would have let you retake it
Reply:The final exam in math, only represents a portion of your overall final grade for the year. If you were doing well in math all year, then you might pass in math, but if your average, was 65, or less, chances are, that you will receive a failing grade for the year in math. Failing in math is not the worst thing in the world, you can always take math again next year. If you do fail your math final, you won't necessarily fail 7th grade this year, if you were doing well in your other subjects.
Reply:Doubt It, But When You Get Into The 8th Grade They Will Pass You
As Long As you Go To School And Do Some Work! Thats WHat They Did To Me The Principle Told Me That He Didnt Want Me There!
Reply:if you had a good grade in math before the final then you have absolutely nothing to worry about.
but if you had a crappy grade before the final then you'll probably have to retake 7th grade math in 8th grade
Reply:u wont...cuz i failed mine and iu gradurated jr high
Reply:Depending on the order of your other math grades, you might pass math. You need to fail 2 or 3 classes to fail a grade, so assuming you have no problems in your other classes, you will definitely pass 7th grade.
This is how you know if you pass a class: the points for each grading period are doubled, while midterms and finals remain the same-
Grading Periods: A=8, B=6, C=4, D=2, F=0
Midterm/Final: A=4, B=3, C=2, D=1, F=0
If both semesters (2 grading periods plus either the midterm or final) each total at least 10 points, you have passed the class. : )
rose
Hi, I wanted to know if I will fail the 7th grade this year b/c I failed my math final.?
If you do there is summer school.
Reply:You probably won't fail. If you were going to fail, your teacher would have needed to already contact your parents. You would have been given a thing called an ILP, which stands for Individual Learning Plan. You might get a D though -- but that's still pasing!
Reply:Well, In my school district rules, If a student fail more than one class you'll be retain. But if you fail but one class, then u have to go to summer school for that class
Good luck
Reply:I doubt that just failing a math final will hold you back a whole grade. It depends on how good or bad your other course grades are and your schools policies. Perhaps you'll have to attend summer school or if your grades in math were already high enough then the failing grade will still factor in as a passing grade. Don't worry.
Reply:depends on where you live and what school you go to
In my town you would have but they would have let you retake it
Reply:The final exam in math, only represents a portion of your overall final grade for the year. If you were doing well in math all year, then you might pass in math, but if your average, was 65, or less, chances are, that you will receive a failing grade for the year in math. Failing in math is not the worst thing in the world, you can always take math again next year. If you do fail your math final, you won't necessarily fail 7th grade this year, if you were doing well in your other subjects.
Reply:Doubt It, But When You Get Into The 8th Grade They Will Pass You
As Long As you Go To School And Do Some Work! Thats WHat They Did To Me The Principle Told Me That He Didnt Want Me There!
Reply:if you had a good grade in math before the final then you have absolutely nothing to worry about.
but if you had a crappy grade before the final then you'll probably have to retake 7th grade math in 8th grade
Reply:u wont...cuz i failed mine and iu gradurated jr high
Reply:Depending on the order of your other math grades, you might pass math. You need to fail 2 or 3 classes to fail a grade, so assuming you have no problems in your other classes, you will definitely pass 7th grade.
This is how you know if you pass a class: the points for each grading period are doubled, while midterms and finals remain the same-
Grading Periods: A=8, B=6, C=4, D=2, F=0
Midterm/Final: A=4, B=3, C=2, D=1, F=0
If both semesters (2 grading periods plus either the midterm or final) each total at least 10 points, you have passed the class. : )
rose
Whats the diffrence from a prim and composite number?and who knows what G.C.F. means in math?
i know what it is,i just wanna see if you know
Whats the diffrence from a prim and composite number?and who knows what G.C.F. means in math?
Greatest common factor is the largest multiple common to a group of numbers. The GCF of 24, 30, and 36 is 6 for example since it is the largest multiple common to all three.
A composite number can be broken down into factors, other than itself and one. For example, 12 = 2 x 6 = 3 x 4 = 12 x 1.
A prime number has only one and itself as factors. For example, 11 = 1 x 11.
Reply:Prime number: No other numbers will "go into" it evenly. Numbers like 3, 5, 7, 11, and 13 are prime.
Composite number: Can be divided into equal parts, or have "factors" other than 1 and itself. Numbers like 4 (2 x 2), 12 (2 x 6, 3 x 4), 15 (3 x 5), and 20 (2 x 10, 4 x 5) are composite.
GCF means "greatest common factor"-- the biggest number that will go into both numbers that you are comparing. The GCF of 6 and 8 is 2, the GCF of 9 and 12 is 3, and the GCF of 30 and 45 is 15.
Reply:greatest common factor prime is a number that cont be factored composite could be factored
Whats the diffrence from a prim and composite number?and who knows what G.C.F. means in math?
Greatest common factor is the largest multiple common to a group of numbers. The GCF of 24, 30, and 36 is 6 for example since it is the largest multiple common to all three.
A composite number can be broken down into factors, other than itself and one. For example, 12 = 2 x 6 = 3 x 4 = 12 x 1.
A prime number has only one and itself as factors. For example, 11 = 1 x 11.
Reply:Prime number: No other numbers will "go into" it evenly. Numbers like 3, 5, 7, 11, and 13 are prime.
Composite number: Can be divided into equal parts, or have "factors" other than 1 and itself. Numbers like 4 (2 x 2), 12 (2 x 6, 3 x 4), 15 (3 x 5), and 20 (2 x 10, 4 x 5) are composite.
GCF means "greatest common factor"-- the biggest number that will go into both numbers that you are comparing. The GCF of 6 and 8 is 2, the GCF of 9 and 12 is 3, and the GCF of 30 and 45 is 15.
Reply:greatest common factor prime is a number that cont be factored composite could be factored
What do you do in math when its a(b+c)d, is that equal to ab + ac +d or abd + acd?
its a math question and i need it answered like now
What do you do in math when its a(b+c)d, is that equal to ab + ac +d or abd + acd?
a(b+c)d is the same as ad(b+c)
Now use the distributive property. Multiply ad by the b to get adb or abd. Then put the plus sign. Finally multiply the ad by the c to get adc or acd. Thus you have the final answer abd + acd.
Reply:abd +acd
Reply:because there is no plus sign in front of the d, its abd+acd
Reply:add b+c then multiply tht answer by a.Then multiply tht answer by d..lol
Reply:a(b+c)d is the same as ad(b+c) so it equals abd+ adc
WHY:
a(b+c)d you move the d to the other side because you are still distrubuting it, so ad(b+c)
then, ad x b = adb
next, ad x c = adc
so, adb + adc is the answer
Reply:abd+acd
[(aXb)+(aXc)]Xd -%26gt; (aXb)Xd+ (aXc)Xd
simplify it to axbxd+ axcxd OR abd+acd
What do you do in math when its a(b+c)d, is that equal to ab + ac +d or abd + acd?
a(b+c)d is the same as ad(b+c)
Now use the distributive property. Multiply ad by the b to get adb or abd. Then put the plus sign. Finally multiply the ad by the c to get adc or acd. Thus you have the final answer abd + acd.
Reply:abd +acd
Reply:because there is no plus sign in front of the d, its abd+acd
Reply:add b+c then multiply tht answer by a.Then multiply tht answer by d..lol
Reply:a(b+c)d is the same as ad(b+c) so it equals abd+ adc
WHY:
a(b+c)d you move the d to the other side because you are still distrubuting it, so ad(b+c)
then, ad x b = adb
next, ad x c = adc
so, adb + adc is the answer
Reply:abd+acd
[(aXb)+(aXc)]Xd -%26gt; (aXb)Xd+ (aXc)Xd
simplify it to axbxd+ axcxd OR abd+acd
Advanced Math: Simplify this... (a/b - c/d) / (1/b - 1/d)?
(a/b - c/d) / (1/b - 1/d)
Advanced Math: Simplify this... (a/b - c/d) / (1/b - 1/d)?
(a/b - c/d) / (1/b - 1/d) find common denominators and add
=[(ad-cb)/bd]/[(d-b)/bd] cancel out the bd
=(ad-cb)/(d-b)
Reply:Top: (ad-cb)/bd
Bottom: (d-b)/bd
Take the reciprocal of bottom into the top.
Cancel out the bd's
=(ad-cb)/(d-b)
Reply:Look at the top part first: a/b - c/d
To get a common denominator, multiply the left fraction by (d/d) and the fraction on the right by (b/b).
So you get: ad/bd - cb/bd
Both fractions now have the same denominator, so you can combine them to get: (ad - cb)/bd
Now look at the bottom part: 1/b - 1/d
Get the common denominator here too; multiply the left fraction by (d/d) and the right fraction by (b/b).
So you get: d/bd - b/bd
Both now have the same denominator, so combine the fractions: (d - b)/bd
So now you have (ad - cb)/bd divided by (d - b)/bd. Flip the second fraction to make it multiplication instead.
(ad - cb)/bd * bd/(d - b)
bd cancels from both fractions, and you end up with (ad - cb)/(d - b)
Reply:a/b-c/d: Take the least common multiple of the denominators which would be bd. Hence a/b-c/d=ad/bd-cb/bd=(ad-cb)/bd.
Similarly, 1/b-1/d
=(d-b)/bd.
So the given equation would be: ({ad-cb)/bd}/{(d-b)/bd}. Multiplying both numerator and denominator by bd/(d-b), the given equation would be:
{(ad-cb)/bd}*bd/{(d-b)}
=ad-cb/(d-b).
Advanced Math: Simplify this... (a/b - c/d) / (1/b - 1/d)?
(a/b - c/d) / (1/b - 1/d) find common denominators and add
=[(ad-cb)/bd]/[(d-b)/bd] cancel out the bd
=(ad-cb)/(d-b)
Reply:Top: (ad-cb)/bd
Bottom: (d-b)/bd
Take the reciprocal of bottom into the top.
Cancel out the bd's
=(ad-cb)/(d-b)
Reply:Look at the top part first: a/b - c/d
To get a common denominator, multiply the left fraction by (d/d) and the fraction on the right by (b/b).
So you get: ad/bd - cb/bd
Both fractions now have the same denominator, so you can combine them to get: (ad - cb)/bd
Now look at the bottom part: 1/b - 1/d
Get the common denominator here too; multiply the left fraction by (d/d) and the right fraction by (b/b).
So you get: d/bd - b/bd
Both now have the same denominator, so combine the fractions: (d - b)/bd
So now you have (ad - cb)/bd divided by (d - b)/bd. Flip the second fraction to make it multiplication instead.
(ad - cb)/bd * bd/(d - b)
bd cancels from both fractions, and you end up with (ad - cb)/(d - b)
Reply:a/b-c/d: Take the least common multiple of the denominators which would be bd. Hence a/b-c/d=ad/bd-cb/bd=(ad-cb)/bd.
Similarly, 1/b-1/d
=(d-b)/bd.
So the given equation would be: ({ad-cb)/bd}/{(d-b)/bd}. Multiplying both numerator and denominator by bd/(d-b), the given equation would be:
{(ad-cb)/bd}*bd/{(d-b)}
=ad-cb/(d-b).
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