Can you help me in this math problem? (2a+3b+c+2d+e) raised to the second power?

Can you solve it?

Can you help me in this math problem? (2a+3b+c+2d+e) raised to the second power?
Lets see...hmmm.....2+3+2=7 %26amp; a+b+c+d+e = abcde...so 7abcde to the power of 2? = 49abcde!...lol
Reply:Ok, I'm a chemist nerd, not a math nerd, but I believe that the entire parenthetical expression must be multiplied by itself. Start this baby slow, first multiply 2a by the whole expression, so 4a^2+6ab+2ac+4da+2e, do this until everything in the parenthesis has been multiplied by everything else. Then add like terms.





Try it on your own by my method above before reading on...








go on...





try it...








Ok, this is what I calculated:


4a^2+12ab+4ac+8ad+4ae+9b^2+6bc


+12bd+6be+c^2+4cd+2ce+4d^2+4de


+e^2 (good lord)


This is probally a homework problem, so learn the method before the test.
Reply:(2a + 3b + c + 2d + e)²





4a² + 9b² + c² + 4d² + e²
Reply:Ah pentanomail theorem. I did it the hard way and so:





4a^2 + 12ab + 4ac +8ad + 4ae + 9b^2 + 6bc + 12bd + 6be + 4cd + 2ce + 4d^2 +4de + e^2.





http://i51.photobucket.com/albums/f354/l...


all the work
Reply:Call your math teacher
Reply:You take teh power and simply attach it to your variables. this makes it 2a2+3b2+c2+2d2+e2 the second 2's are exponents.
Reply:I disagree with everyone so far. I get (4a^2+9b^2+c^2+4d^2+e^2) (F.Y.I. ^ is the symbol for exponents)
Reply:multiply it with the original equation
Reply:(2a+3b+c+2d+e) 2 = 4a2+9b2 +c2+4d2+e2
Reply:(2a+3b+c+2d+e)^2 = ?





Answer: 4a^2+9b^2+4d^2+c^2+4d^2+e^2.





Simplifying:


(2a)^2 + (3b)^2 + (2d)^2 + c^2 + (2d)^2 + e^2 =





4a^2+9b^2+4d^2+c^2+4d^2+e^2.





Please note: ^ represents exponent.