Challenging math problem. 60ml of solution A is mixed with 120ml of solution B to produce solution C with....?

60ml of solution A is mixed with 120ml of solution B to produce solution C with 8% pure acid. If 80ml of solution A is mixed with 40ml of solution B. 10% acid is produced. how much % acid is in Solution A.





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Challenging math problem. 60ml of solution A is mixed with 120ml of solution B to produce solution C with....?
let there be x% acidic of sol. A and y% acidic of sol. B.





60x + 120y = (60+120)*8 = 180*8


x + 2y = 3*8 = 24





80x + 40y = (80+40)*10 = 120*10


2x + y = 3*10 = 30





4x - x = 60 - 24


3x = 36


x = 12%
Reply:first mixed=180ml


8%of it is 14.4ml of pure acid


2nd mixed=120ml


10% is 12ml of pure acid


let x be the concentration of A


let y be the concentration of B


60x+120y=14.4


80x+40y=12


solve for x and y


240x-60x=36-14.4


180x=21.6


x=12%


therefore the solution A is 12%

nil