8c-(c-5)>c=17...math help please!?

what is c?

8c-(c-5)%26gt;c=17...math help please!?
8c-c+5%26gt;c+17


7c+5%26gt;c+17


7c+5-5%26gt;c+17-5


7c-c%26gt;c-c+12


6c%26gt;12


c%26gt;2
Reply:8c - c + 5 %26gt;c-7


7c + 5 %26gt; c - 7


6c + 5%26gt;-7


6c %26gt; -12


c%26gt;-2
Reply:ALRIGHT, I THINK YOU MEANT THIS:





8c - (c-5) %26gt; c -17





DISTRIBUTE THE NEGATIVE SIGN.





8c - c + 5 %26gt; c - 17





ADD LIKE TERMS.





7c + 5 %26gt; c - 17





SUBTRACT BOTH SIDES BY "-c"





6c + 5 %26gt; - 17





ADD BOTH SIDES BY "-5"





6c %26gt; - 12





DIVIDE BOTH SIDES BY 6.





c %26gt; -2
Reply:8c-(c-5)%26gt;c+17 Remove brackets first


8c -c +5 %26gt; c+17 Collect terms together


7c + 5 %26gt; c+17 Take c from the right side to the left


7c - c +5 %26gt; 17 Collect terms again


6c +5 %26gt; 17 Take the 5 to the right of the equation


6c %26gt; 17 -5 Collect terms again


6c %26gt; 12 Divide both sides by 6 to get just c on its own


c %26gt; 2





I hope this helps?!